Home
Class 12
PHYSICS
A square loop EFGH of side a, mass m and...

A square loop EFGH of side a, mass m and total resistance R is falling under gravity in a region of transverse non - uniform magnetic field given by `B=B_(0)^(y)/(a)` =, where `B_(0)` is a positive constant and y is the position of side EF of the loop. If at some instant the speed of the loop is v, then the total Lorentz acting on the loop is

A

`F=(B_(0)^(2)a^(2)v)/(2H)`

B

`F=(2B_(0)^(2)a^(2)v)/(R)`

C

`F=(B_(0)^(2)a^(2)v)/(R)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

The magnetic field I nan reigion is given by B=B_(0) (X)/(a)K . A Squrae edges along the x and y axis. The loop is moved with a constant velocity . The emf induced in the loop is

A square loop ABCD of side l is moving the xy plane with velocity vecv=betat hatj .There exists a non-uniform magnetic field vecB=-B_(0)(1+alphay^(2)) hatk (y gt 0) , where B_(0) and alpha are positive constants. Initially, the upper wire of the loop is at y=0 .Find the induced voltage across the resistance R as a function of time.Neglect the magnetic force due to induced current.

A square loop of side 'a' is placed in x-y plane as shown in figure. In this region there is non-uniform time dependent magnetic field vec B= (cy^3 t^2) veck , [where t is time and c is constant] then magnitude of emf induced in loop is

A circular loop of radius R carrying current I is kept in XZ plane. A uniform and constant magnetic field vecB=(B_(0)hati+2B_(0)hatj+3B_(0)hatk) exists in the region ( B_(0)- a positive constant). Then the magnitude of the torque acting on the loop will be

A rectangular loop of sides 20 cm and 10 cm carries a current of 5.0 A. A uniform magnetic field of magnituded 0.20 T exists parallel ot the longer side of the loop (a) What is the force acting on the loop? (b) what is the torque acting on the loop?

Figure shows a conducting Rectangular loop of electrical resistance R. There exists a uniform magnetic field given by vecB=B_(0)(10t^(2)-5t)hat(k) in the region. The current in the loop at

A conducting metal circular-wire-loop of radius r is placed perpendicular to a magnetic field which varies with time as B = B_0e^(-t//tau) , where B_0 and tau are constants, at time = 0. If the resistance of the loop is R then the heat generated in the loop after a long time (t to oo) is :

A conducting metal circular-wire-loop of radius r is placed perpendicular to a magnetic field which varies with time as B = B_0e^(-t//tau) , where B_0 and tau are constants, at time = 0. If the resistance of the loop is R then the heat generated in the loop after a long time (t to oo) is :

A conducting square loop of side l and resistance R moves in its plane with a uniform velocity v perpendicular ot one of its sides. A uniform and constant magnetic field B exists along the perpendicualr ot the plane of the loop as shown in . The current induced in the loop is

A square loop of sides 10 cm carries a current of 10 A .A uniform magnetic field of magnitude 0.20 T exists parallel to one of the side of the loop.(a)What is the force acting on the loop? (b)What is the torque acting on the loop?