Hydrolysis of `PI_(3)` yield

Options

A. a monobasic acid and a dibasic acid
B. a monobasic acid and a salt
C. a monobasic acid and tribasic acid
D. a monoacid base and a dibasic acid.

Answer

To solve the question regarding the hydrolysis of \( PI_3 \), we will break it down into a series of steps.

### Step 1: Understand the Hydrolysis Reaction
Hydrolysis involves the reaction of a compound with water. In this case, we are looking at the hydrolysis of phosphorus triiodide (\( PI_3 \)) with water (\( H_2O \)).

### Step 2: Write the Reaction
The hydrolysis of \( PI_3 \) can be represented as:
\[ PI_3 + 3H_2O \rightarrow H_3PO_3 + 3HI \]
Here, \( H_3PO_3 \) is phosphorous acid, and \( HI \) is hydroiodic acid.

### Step 3: Identify the Products
From the reaction, we can identify the products:
- \( H_3PO_3 \) is a dibasic acid (it can donate two protons).
- \( HI \) is a monobasic acid (it can donate one proton).

### Step 4: Classify the Acids
- **Dibasic Acid**: An acid that can donate two protons (e.g., \( H_3PO_3 \)).
- **Monobasic Acid**: An acid that can donate one proton (e.g., \( HI \)).

### Step 5: Conclusion
Thus, the hydrolysis of \( PI_3 \) yields a dibasic acid (\( H_3PO_3 \)) and a monobasic acid (\( HI \)). Therefore, the correct answer is:
- **Dibasic acid and a monobasic acid**.

### Final Answer:
The hydrolysis of \( PI_3 \) yields a dibasic acid and a monobasic acid.

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