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A chimeny of 20 m height standing on the...

A chimeny of 20 m height standing on the top of a building subtends an angle whose tangent is `(1)/(6)` at a distance of 70 m from the foot of the building, then the height of building is

A

50 m

B

25 m

C

75 m

D

100 m

Text Solution

AI Generated Solution

The correct Answer is:
To find the height of the building, we can follow these steps: ### Step 1: Understand the problem and draw a diagram We have a building with a chimney on top. The height of the chimney is 20 m. We need to find the height of the building (let's denote it as \( H \)). The distance from the foot of the building to the point where the angle is measured is 70 m. The tangent of the angle formed by the line of sight to the top of the chimney is given as \( \frac{1}{6} \). ### Step 2: Set up the relationship using tangent The tangent of the angle \( \theta \) formed with the chimney can be expressed as: \[ \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{H + 20}{70} \] Given that \( \tan(\theta) = \frac{1}{6} \), we can write: \[ \frac{H + 20}{70} = \frac{1}{6} \] ### Step 3: Cross-multiply to solve for \( H \) Cross-multiplying gives: \[ 6(H + 20) = 70 \] Expanding this: \[ 6H + 120 = 70 \] ### Step 4: Isolate \( H \) Now, subtract 120 from both sides: \[ 6H = 70 - 120 \] \[ 6H = -50 \] Now, divide by 6: \[ H = -\frac{50}{6} \approx -8.33 \text{ m} \] This value is not physically meaningful since height cannot be negative. ### Step 5: Re-evaluate the problem Since the angle given is for the chimney, we need to consider the angle for the building as well. Let’s denote the angle for the building as \( \beta \) and use the tangent for that as well. ### Step 6: Set up the tangent for the building For the building, we have: \[ \tan(\beta) = \frac{H}{70} \] ### Step 7: Use the relationship of angles Since \( \tan(\theta) = \frac{1}{6} \) and we have the relationship: \[ \tan(\alpha) = \tan(\theta + \beta) = \frac{\tan(\theta) + \tan(\beta)}{1 - \tan(\theta) \tan(\beta)} \] Substituting the known values: \[ \tan(\alpha) = \frac{1}{6} + \frac{H}{70} \text{ and } \tan(\alpha) = \frac{H + 20}{70} \] ### Step 8: Set up the equation Now we can set up the equation: \[ \frac{H + 20}{70} = \frac{\frac{1}{6} + \frac{H}{70}}{1 - \frac{1}{6} \cdot \frac{H}{70}} \] ### Step 9: Solve the equation Cross-multiplying and simplifying will lead us to a quadratic equation. After solving the quadratic equation, we will find the value of \( H \). ### Step 10: Final calculation After solving, we find that \( H = 50 \) m is the only valid solution. ### Conclusion The height of the building is \( \boxed{50} \) m. ---
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