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A carnot engine has efficiency 1//5 . Ef...

A carnot engine has efficiency `1//5` . Efficiency becomes `1//3` when temperature of sink is decreased by 50 K What is the temperature of sink ?

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To solve the problem, we will follow these steps: ### Step 1: Understand the Efficiency of a Carnot Engine The efficiency (η) of a Carnot engine is given by the formula: \[ \eta = 1 - \frac{T_2}{T_1} \] where \(T_1\) is the temperature of the heat source (hot reservoir) and \(T_2\) is the temperature of the sink (cold reservoir). ### Step 2: Set Up the Initial Condition From the problem, we know that the efficiency is initially \( \frac{1}{5} \). Therefore, we can write: \[ \frac{1}{5} = 1 - \frac{T_2}{T_1} \] Rearranging this gives: \[ \frac{T_2}{T_1} = 1 - \frac{1}{5} = \frac{4}{5} \] Thus, we can express \(T_1\) in terms of \(T_2\): \[ T_1 = \frac{5}{4} T_2 \quad \text{(Equation 1)} \] ### Step 3: Set Up the Condition After Decreasing the Sink Temperature When the temperature of the sink is decreased by 50 K, the new efficiency becomes \( \frac{1}{3} \). The new temperature of the sink is \(T_2 - 50\). Therefore, we can write: \[ \frac{1}{3} = 1 - \frac{T_2 - 50}{T_1} \] Rearranging this gives: \[ \frac{T_2 - 50}{T_1} = 1 - \frac{1}{3} = \frac{2}{3} \] Thus, we can express \(T_1\) in terms of \(T_2\) again: \[ T_1 = \frac{3}{2}(T_2 - 50) \quad \text{(Equation 2)} \] ### Step 4: Equate the Two Expressions for \(T_1\) Now we have two expressions for \(T_1\): 1. \(T_1 = \frac{5}{4} T_2\) 2. \(T_1 = \frac{3}{2}(T_2 - 50)\) Setting these equal to each other: \[ \frac{5}{4} T_2 = \frac{3}{2}(T_2 - 50) \] ### Step 5: Solve for \(T_2\) Cross-multiplying to eliminate the fractions: \[ 5 \cdot 2 T_2 = 3 \cdot 4 (T_2 - 50) \] This simplifies to: \[ 10 T_2 = 12 T_2 - 600 \] Rearranging gives: \[ 10 T_2 - 12 T_2 = -600 \] \[ -2 T_2 = -600 \] \[ T_2 = 300 \, \text{K} \] ### Step 6: Find \(T_1\) Now substitute \(T_2 = 300\) K back into Equation 1 to find \(T_1\): \[ T_1 = \frac{5}{4} \times 300 = 375 \, \text{K} \] ### Final Answer The temperature of the sink \(T_2\) is: \[ \boxed{300 \, \text{K}} \]
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