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The number of tangents that can be drawn...

The number of tangents that can be drawn from (2, 0) to the curve `y=x^(6)` is/are

A

0

B

1

C

2

D

3

Text Solution

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The correct Answer is:
To find the number of tangents that can be drawn from the point (2, 0) to the curve \( y = x^6 \), we can follow these steps: ### Step 1: Set up the problem We want to find the number of tangents from the point (2, 0) to the curve \( y = x^6 \). Let the point of tangency on the curve be \( (x_1, y_1) \), where \( y_1 = x_1^6 \). ### Step 2: Find the slope of the tangent The slope \( m \) of the tangent line at the point \( (x_1, y_1) \) can be expressed as: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Here, \( (x_2, y_2) = (2, 0) \) and \( y_1 = x_1^6 \). Thus, \[ m = \frac{0 - x_1^6}{2 - x_1} = \frac{-x_1^6}{2 - x_1} \] ### Step 3: Find the derivative of the curve The derivative of \( y = x^6 \) gives us the slope of the tangent at any point \( x_1 \): \[ \frac{dy}{dx} = 6x^5 \] At the point of tangency \( (x_1, y_1) \), the slope of the tangent line is: \[ m = 6x_1^5 \] ### Step 4: Set the slopes equal Since both expressions represent the slope of the tangent line at the point of tangency, we can set them equal: \[ \frac{-x_1^6}{2 - x_1} = 6x_1^5 \] ### Step 5: Cross-multiply and simplify Cross-multiplying gives us: \[ -x_1^6 = 6x_1^5(2 - x_1) \] Expanding the right side: \[ -x_1^6 = 12x_1^5 - 6x_1^6 \] Rearranging terms: \[ -x_1^6 + 6x_1^6 - 12x_1^5 = 0 \] This simplifies to: \[ 5x_1^6 - 12x_1^5 = 0 \] ### Step 6: Factor out common terms Factoring out \( x_1^5 \): \[ x_1^5(5x_1 - 12) = 0 \] This gives us two factors: 1. \( x_1^5 = 0 \) which implies \( x_1 = 0 \) 2. \( 5x_1 - 12 = 0 \) which implies \( x_1 = \frac{12}{5} \) ### Step 7: Determine the number of tangents We have found two values for \( x_1 \): 1. \( x_1 = 0 \) 2. \( x_1 = \frac{12}{5} \) Each value corresponds to a distinct tangent line from the point (2, 0) to the curve \( y = x^6 \). Therefore, the total number of tangents that can be drawn from the point (2, 0) to the curve is **2**. ### Final Answer The number of tangents that can be drawn from (2, 0) to the curve \( y = x^6 \) is **2**. ---
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