Home
Class 12
MATHS
If the line y=x-1 bisects two chords of ...

If the line `y=x-1` bisects two chords of the parabola `y^(2)=4bx` which are passing through the point `(b, -2b)`, then the length of the latus rectum can be equal to

A

3

B

5

C

6

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the length of the latus rectum of the parabola given that the line \( y = x - 1 \) bisects two chords of the parabola \( y^2 = 4bx \) that pass through the point \( (b, -2b) \). ### Step-by-Step Solution: 1. **Identify the parabola and its properties:** The equation of the parabola is given by \( y^2 = 4bx \). The length of the latus rectum of a parabola of the form \( y^2 = 4px \) is \( 4p \). Here, \( p = b \), so the length of the latus rectum is \( 4b \). 2. **Find the coordinates of the point through which the chords pass:** The chords pass through the point \( (b, -2b) \). 3. **Substitute the point into the parabola's equation:** Substitute \( x = b \) and \( y = -2b \) into the parabola's equation: \[ (-2b)^2 = 4b(b) \] Simplifying gives: \[ 4b^2 = 4b^2 \] This confirms that the point \( (b, -2b) \) lies on the parabola. 4. **Find the intersection of the line with the parabola:** The line \( y = x - 1 \) intersects the parabola. Substitute \( y \) in the parabola's equation: \[ (x - 1)^2 = 4bx \] Expanding this gives: \[ x^2 - 2x + 1 = 4bx \] Rearranging results in: \[ x^2 - (4b + 2)x + 1 = 0 \] 5. **Use the property of the bisector:** Since the line bisects the chords, the sum of the roots of the quadratic equation (which represent the x-coordinates of the intersection points) is equal to the x-coordinate of the midpoint of the chord. The sum of the roots \( S \) is given by: \[ S = 4b + 2 \] The midpoint of the chord can be calculated using the line \( y = x - 1 \). The midpoint's x-coordinate is given by \( h \) and the y-coordinate is \( h - 1 \). 6. **Set up the equation for the midpoint:** The midpoint of the chord can also be expressed as: \[ \frac{x_1 + x_2}{2} = h \] Thus, \( x_1 + x_2 = 2h \). Equating gives: \[ 2h = 4b + 2 \implies h = 2b + 1 \] 7. **Substitute back into the parabola's equation:** Substitute \( h \) back into the parabola's equation to find the condition on \( b \): \[ (2b + 1 - 1)^2 = 4b(2b + 1) \] Simplifying gives: \[ (2b)^2 = 8b^2 + 4b \implies 4b^2 = 8b^2 + 4b \] Rearranging gives: \[ 4b^2 + 4b = 0 \implies 4b(b + 1) = 0 \] Thus, \( b = 0 \) or \( b = -1 \). 8. **Determine the length of the latus rectum:** Since \( b \) must be positive for the parabola to be defined, we only consider \( b = 1 \). Therefore, the length of the latus rectum is: \[ 4b = 4 \times 1 = 4 \] ### Conclusion: The length of the latus rectum can be equal to **4**.
Promotional Banner

Similar Questions

Explore conceptually related problems

If the parabola y^(2) = 4ax passes through the point (3,2) , then the length of its latus rectum is

The parabola y^(2) = 4px passes through the point (3, -2). The length of the latus-rectum is …………..

If the parabola y^(2)=4ax passes through the point (4,5) , find the length of its latus rectum.

If the parabola y^2=4a x\ passes through the point (3,2) then find the length of its latus rectum.

If the parabola y^2=4a x\ passes through the point (3,2) then find the length of its latus rectum.

The parabola y^2=4px passes thrugh the point (3,-2) . Obtain the length of the latus rectum and the coordinates of the focus.

The parabola y^(2)=4ax passes through the point (2,-6) . Find the length of its latus rectum.

If the parabola of y^2=4ax passes through the point (3,2), find the length of its latus rectum.

If the parabola y^(2)=4ax passes through the (4,-8) then find the length of latus rectum and the co-ordinates of focus.

The parabola y^(2) = 2ax passes through the point (-2,1) .The length of its latus rectum is