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If velocity, force and time are taken as...

If velocity, force and time are taken as the fundamental quantities, them using dimensional analysis choose the correct dimensional formula for mass among the following. [K is a dimensionless constant]

A

`Q=Kv^(-1)FT`

B

`Q=Kv^(3)FT^(2)`

C

`Q=2Kv^(-2)FT`

D

`Q=3Kv^(2)Ft`

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimensional formula for mass using velocity, force, and time as fundamental quantities, we can follow these steps: ### Step 1: Define the Dimensional Formula Assume the dimensional formula for mass \( Q \) can be expressed in terms of velocity \( V \), force \( F \), and time \( T \) as: \[ Q = K \cdot V^a \cdot F^b \cdot T^c \] where \( K \) is a dimensionless constant, and \( a, b, c \) are the powers we need to determine. ### Step 2: Write the Dimensional Formulas The dimensional formulas for the quantities involved are: - Velocity \( V \): \( [V] = L^1 T^{-1} \) - Force \( F \): \( [F] = M^1 L^1 T^{-2} \) - Time \( T \): \( [T] = T^1 \) ### Step 3: Substitute the Dimensional Formulas Substituting the dimensional formulas into our equation gives: \[ Q = K \cdot (L^1 T^{-1})^a \cdot (M^1 L^1 T^{-2})^b \cdot (T^1)^c \] ### Step 4: Combine the Dimensions Now, combining the dimensions, we have: \[ Q = K \cdot M^b \cdot L^{a+b} \cdot T^{-a - 2b + c} \] ### Step 5: Equate to the Dimensional Formula for Mass The dimensional formula for mass is: \[ [M] = M^1 L^0 T^0 \] This gives us the following equations by equating the powers of \( M \), \( L \), and \( T \): 1. \( b = 1 \) (for \( M \)) 2. \( a + b = 0 \) (for \( L \)) 3. \( -a - 2b + c = 0 \) (for \( T \)) ### Step 6: Solve the Equations From equation (1), we have: \[ b = 1 \] Substituting \( b = 1 \) into equation (2): \[ a + 1 = 0 \implies a = -1 \] Substituting \( a = -1 \) and \( b = 1 \) into equation (3): \[ -(-1) - 2(1) + c = 0 \implies 1 - 2 + c = 0 \implies c = 1 \] ### Step 7: Write the Dimensional Formula for Mass Now substituting the values of \( a \), \( b \), and \( c \) back into the original equation for \( Q \): \[ Q = K \cdot V^{-1} \cdot F^1 \cdot T^1 \] Thus, the dimensional formula for mass in terms of velocity, force, and time is: \[ Q = K \cdot V^{-1} \cdot F \cdot T \] ### Final Answer The correct dimensional formula for mass is: \[ Q = K \cdot V^{-1} \cdot F \cdot T \]
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