Number of metal oxygen bonds in the orange - red coloured compound formed when `NaCl` reacts with `K_(2)Cr_(2)O_(7)` and `H_(2)SO_(4)`.

Options

A. 2
B. 4
C. 6
D. 0

Answer

To solve the question regarding the number of metal-oxygen bonds in the orange-red colored compound formed when NaCl reacts with K₂Cr₂O₇ and H₂SO₄, we will follow these steps:

### Step 1: Identify the Reaction
The reaction involves NaCl, K₂Cr₂O₇, and H₂SO₄. When these react, the products formed include CrO₂Cl₂, NaHSO₄, KHSO₄, and water.

### Step 2: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction is:
\[ 4 \text{NaCl} + \text{K}_2\text{Cr}_2\text{O}_7 + 6 \text{H}_2\text{SO}_4 \rightarrow 2 \text{CrO}_2\text{Cl}_2 + 4 \text{NaHSO}_4 + 2 \text{KHSO}_4 + 3 \text{H}_2\text{O} \]

### Step 3: Identify the Compound
The compound of interest is CrO₂Cl₂, which is the orange-red colored compound formed in the reaction.

### Step 4: Determine the Structure of CrO₂Cl₂
The structure of CrO₂Cl₂ can be represented as:
- Chromium (Cr) is the central metal atom.
- There are two double bonds with oxygen (O) and two single bonds with chlorine (Cl).

### Step 5: Count the Metal-Oxygen Bonds
In CrO₂Cl₂:
- There are 2 double bonds between chromium and oxygen.
- Each double bond counts as 2 metal-oxygen bonds.

Thus, the total number of metal-oxygen bonds is:
\[ 2 \text{ (from O=Cr)} + 2 \text{ (from O=Cr)} = 4 \text{ metal-oxygen bonds} \]

### Final Answer
The number of metal-oxygen bonds in the compound CrO₂Cl₂ is **4**.

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