The total number of moles of neutrons present in 108 mL `H_(2)O(l)` are

Answer

To find the total number of moles of neutrons present in 108 mL of water (H₂O), we can follow these steps:

### Step 1: Determine the composition of water
Water (H₂O) consists of two hydrogen (H) atoms and one oxygen (O) atom.

### Step 2: Find the number of neutrons in each atom
- **Hydrogen (H)**:
- Atomic number (Z) = 1 (number of protons)
- Mass number (A) = 1 (protons + neutrons)
- Neutrons in H = A - Z = 1 - 1 = 0

- **Oxygen (O)**:
- Atomic number (Z) = 8 (number of protons)
- Mass number (A) = 16 (protons + neutrons)
- Neutrons in O = A - Z = 16 - 8 = 8

### Step 3: Calculate the total number of neutrons in one molecule of water
In one molecule of water (H₂O):
- Total neutrons = (2 × Neutrons in H) + (1 × Neutrons in O)
- Total neutrons = (2 × 0) + (1 × 8) = 8 neutrons

### Step 4: Calculate the mass of water
Given that the density of water is 1 g/mL, the mass of 108 mL of water is:
- Mass = Volume × Density = 108 mL × 1 g/mL = 108 g

### Step 5: Calculate the number of moles of water
The molar mass of water (H₂O) is:
- Molar mass = (2 × Atomic mass of H) + (1 × Atomic mass of O) = (2 × 1) + (16) = 18 g/mol

Now, calculate the number of moles of water:
- Moles of water = Mass of water / Molar mass of water
- Moles of water = 108 g / 18 g/mol = 6 moles

### Step 6: Calculate the total number of moles of neutrons
Since each molecule of water contains 8 neutrons, the total number of moles of neutrons can be calculated as:
- Total moles of neutrons = Moles of water × Neutrons per molecule
- Total moles of neutrons = 6 moles × 8 = 48 moles

### Final Answer
The total number of moles of neutrons present in 108 mL of water is **48 moles**.

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