The molecule which contains maximum number of lone Pair is

Options

A. `IF_7`
B. `XeF_6`
C. `XeF_4`
D. `XeF_2`

Answer

To determine which molecule contains the maximum number of lone pairs, we will analyze the given compounds of fluorine step by step.

### Step 1: Analyze IF7
- **Valence Electrons of Iodine (I)**: Iodine has 7 valence electrons.
- **Bonds with Fluorine**: In IF7, iodine forms 7 sigma bonds with 7 fluorine atoms.
- **Calculation of Lone Pairs**: Since all 7 valence electrons are used to form bonds, there are no remaining electrons for lone pairs.
- **Lone Pairs in IF7**: 0 lone pairs.

### Step 2: Analyze XeF6
- **Valence Electrons of Xenon (Xe)**: Xenon has 8 valence electrons.
- **Bonds with Fluorine**: In XeF6, xenon forms 6 sigma bonds with 6 fluorine atoms.
- **Calculation of Lone Pairs**: 8 total valence electrons - 6 used in bonding = 2 remaining electrons.
- **Lone Pairs in XeF6**: 1 lone pair.

### Step 3: Analyze XeF4
- **Bonds with Fluorine**: In XeF4, xenon forms 4 sigma bonds with 4 fluorine atoms.
- **Calculation of Lone Pairs**: 8 total valence electrons - 4 used in bonding = 4 remaining electrons.
- **Lone Pairs in XeF4**: 2 lone pairs.

### Step 4: Analyze XeF2
- **Bonds with Fluorine**: In XeF2, xenon forms 2 sigma bonds with 2 fluorine atoms.
- **Calculation of Lone Pairs**: 8 total valence electrons - 2 used in bonding = 6 remaining electrons.
- **Lone Pairs in XeF2**: 3 lone pairs.

### Conclusion
After analyzing all the compounds:
- IF7 has 0 lone pairs.
- XeF6 has 1 lone pair.
- XeF4 has 2 lone pairs.
- XeF2 has 3 lone pairs.

Thus, the molecule that contains the maximum number of lone pairs is **XeF2**, which has **3 lone pairs**.

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