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Let f (x) = 10 - |x-5| , x in R, then th...

Let f (x) = 10 - |x-5| , `x in R,` then the set of all values of x at which f (f(x)) is not differentiable is

A

{0,5,10}

B

{5,10}

C

{0,5,10,15}

D

{5,10,15}

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the set of all values of \( x \) at which \( f(f(x)) \) is not differentiable, where \( f(x) = 10 - |x - 5| \). ### Step 1: Analyze the function \( f(x) \) The function \( f(x) = 10 - |x - 5| \) can be rewritten based on the definition of absolute value: - For \( x < 5 \): \[ f(x) = 10 - (5 - x) = x + 5 \] - For \( x = 5 \): \[ f(5) = 10 - |5 - 5| = 10 \] - For \( x > 5 \): \[ f(x) = 10 - (x - 5) = 15 - x \] Thus, we can summarize \( f(x) \) as: \[ f(x) = \begin{cases} x + 5 & \text{if } x < 5 \\ 10 & \text{if } x = 5 \\ 15 - x & \text{if } x > 5 \end{cases} \] ### Step 2: Find \( f(f(x)) \) Now we need to find \( f(f(x)) \). We will consider the three cases for \( f(x) \): 1. **Case 1: \( x < 5 \)** - Here, \( f(x) = x + 5 \). - Since \( x + 5 \geq 5 \) for \( x < 5 \), we have: \[ f(f(x)) = f(x + 5) = 15 - (x + 5) = 10 - x \] 2. **Case 2: \( x = 5 \)** - Here, \( f(5) = 10 \). - Thus: \[ f(f(5)) = f(10) = 15 - 10 = 5 \] 3. **Case 3: \( x > 5 \)** - Here, \( f(x) = 15 - x \). - Since \( 15 - x \leq 10 \) for \( x \geq 5 \), we consider two subcases: - If \( 5 < x < 10 \): \[ f(f(x)) = f(15 - x) = 10 - (15 - x) = x - 5 \] - If \( x = 10 \): \[ f(f(10)) = f(5) = 10 \] - If \( x > 10 \): \[ f(f(x)) = f(15 - x) = 10 - (x - 15) = 25 - x \] ### Step 3: Determine where \( f(f(x)) \) is not differentiable The function \( f(f(x)) \) is given by: \[ f(f(x)) = \begin{cases} 10 - x & \text{if } x < 5 \\ 5 & \text{if } x = 5 \\ x - 5 & \text{if } 5 < x < 10 \\ 10 & \text{if } x = 10 \\ 25 - x & \text{if } x > 10 \end{cases} \] Now we check the points where \( f(f(x)) \) changes its definition: - At \( x = 5 \): The left-hand limit is \( 10 - 5 = 5 \) and the right-hand limit is \( 5 \). The function is continuous but not differentiable since the derivative changes from \(-1\) to \(0\). - At \( x = 10 \): The left-hand limit is \( 10 - 10 = 0 \) and the right-hand limit is \( 25 - 10 = 15 \). The function is continuous but not differentiable since the derivative changes from \(1\) to \(-1\). ### Conclusion The points where \( f(f(x)) \) is not differentiable are \( x = 0, 5, 10 \). Thus, the set of all values of \( x \) at which \( f(f(x)) \) is not differentiable is: \[ \{0, 5, 10\} \]
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