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In a pond of water, a flame is held 2 m ...

In a pond of water, a flame is held 2 m above the surface of the water. A fish is at depth of 4 m from the water surface. Refractive index of water is `(4)/(3)`. The apparent height of the flame from the eyes of fish is -

A

5.5 m

B

6 m

C

`(8)/(3)m`

D

`(20)/(3)m`

Text Solution

AI Generated Solution

The correct Answer is:
To find the apparent height of the flame from the eyes of the fish, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Height of the flame above the water surface, \( h_1 = 2 \, \text{m} \) - Depth of the fish below the water surface, \( h_2 = 4 \, \text{m} \) - Refractive index of water, \( \mu = \frac{4}{3} \) 2. **Calculate the Apparent Height of the Flame Above the Water Surface:** - The formula for apparent height when viewing from a medium with a different refractive index is given by: \[ h_1' = \frac{h_1}{\mu} \] - Substituting the values: \[ h_1' = \frac{2 \, \text{m}}{\frac{4}{3}} = 2 \times \frac{3}{4} = \frac{6}{4} = \frac{3}{2} \, \text{m} = 1.5 \, \text{m} \] 3. **Determine the Total Apparent Height from the Fish's Perspective:** - The fish is at a depth of \( 4 \, \text{m} \) below the water surface. Therefore, the total apparent height \( H \) from the fish's eyes to the flame is: \[ H = h_1' + h_2 \] - Substituting the values: \[ H = 1.5 \, \text{m} + 4 \, \text{m} = 5.5 \, \text{m} \] 4. **Final Result:** - The apparent height of the flame from the eyes of the fish is \( 5.5 \, \text{m} \). ### Summary: The apparent height of the flame from the eyes of the fish is \( 5.5 \, \text{m} \).
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