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A particle is projected with velocity v0...

A particle is projected with velocity v0 along x-axis. The deceleration of the particle is proportional to the square of the distance from the origin i.e.`a=-alphax ^(2) ` , the distance at which the particle stops is

A

`sqrt((3v_(0))/(2))`

B

`((v_(0)^(2))/(3))^(1//3)`

C

`((2v_(0)^(2))/(3))^(1//3)`

D

`((3v_(0)^(2))/(2))^(1//3)`

Text Solution

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The correct Answer is:
D
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