A sample of air which is free from `CO_(2)`, is used to heat Na metal at `350^(@)C` to form X. X has the property to absorb `CO_(2)` and form Y. Identify ''X'' and ''Y'' respectively.

Options

A. `Na_(2)O and O_(2)`
B. `Na_(2)O_(2) and O_(2)`
C. `NaO_(2) and O_(2)`
D. `Na_(2)O_(2) and O_(3)`

Answer

To solve the problem step by step, we will analyze the reactions involved and identify the compounds formed.

### Step 1: Identify the Reaction of Sodium with Oxygen
Given that a sample of air free from CO2 is used to heat sodium (Na) at 350°C, we know that sodium will react with the available oxygen (O2) in the air. The reaction can be represented as:

\[ 4 \text{Na} + \text{O}_2 \rightarrow 2 \text{Na}_2\text{O} \]

However, at higher temperatures, sodium can also form sodium peroxide (Na2O2):

\[ 2 \text{Na} + \text{O}_2 \rightarrow \text{Na}_2\text{O}_2 \]

Thus, we can conclude that the product formed (X) when sodium reacts with oxygen at 350°C is sodium peroxide (Na2O2).

### Step 2: Identify the Reaction of Sodium Peroxide with Carbon Dioxide
Next, we need to analyze how sodium peroxide (X) interacts with carbon dioxide (CO2). Sodium peroxide has the ability to absorb CO2, and the reaction can be represented as follows:

\[ \text{Na}_2\text{O}_2 + \text{CO}_2 \rightarrow \text{Na}_2\text{CO}_3 + \text{O}_2 \]

In this reaction, sodium peroxide reacts with carbon dioxide to form sodium carbonate (Na2CO3) and oxygen (O2).

### Conclusion
From the above steps, we can identify:
- **X** (the product formed from the reaction of sodium with oxygen) is **sodium peroxide (Na2O2)**.
- **Y** (the product formed when sodium peroxide absorbs CO2) is **oxygen (O2)**.

Thus, the final answer is:
- **X = Na2O2**
- **Y = O2**