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If DeltaH is the change in enthylpy and ...

If `DeltaH` is the change in enthylpy and `DeltaU`, the change in internal energy accompanying a gaseous reactant then

A

`DeltaH` is always greater than `DeltaE`

B

`Delta H lt DeltH` only if the number of moles of the products is greater than the number of moles of the reactants

C

`DeltaH` is always less than `DeltaE`

D

`Delta H lt Delta E` only if the number of moles of products is less than the number of moles of the reactants

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the relationship between the change in enthalpy (ΔH) and the change in internal energy (ΔU) for a gaseous reactant, we can follow these steps: ### Step 1: Understand the relationship between ΔH and ΔU The relationship between the change in enthalpy (ΔH) and the change in internal energy (ΔU) is given by the equation: \[ \Delta H = \Delta U + \Delta n_g RT \] where: - Δn_g = change in the number of moles of gas (nP - nR) - R = universal gas constant - T = temperature in Kelvin ### Step 2: Analyze the three possible conditions for Δn_g 1. **Δn_g < 0**: This occurs when the number of moles of reactants (nR) is greater than the number of moles of products (nP). In this case, ΔH can be expressed as: \[ \Delta H = \Delta U - |\Delta n_g| RT \] Here, since we are subtracting a positive term from ΔU, it follows that: \[ \Delta H < \Delta U \] 2. **Δn_g > 0**: This occurs when the number of moles of products (nP) is greater than the number of moles of reactants (nR). In this case, ΔH can be expressed as: \[ \Delta H = \Delta U + \Delta n_g RT \] Here, since we are adding a positive term to ΔU, it follows that: \[ \Delta H > \Delta U \] 3. **Δn_g = 0**: This occurs when the number of moles of products (nP) is equal to the number of moles of reactants (nR). In this case, ΔH can be expressed as: \[ \Delta H = \Delta U \] ### Step 3: Evaluate the options based on the analysis - **Option 1**: "ΔH is always greater than ΔU" - This is incorrect because ΔH can be less than ΔU when Δn_g < 0. - **Option 2**: "ΔH is less than ΔU only if the number of moles of product is greater than the number of moles of reactant" - This is incorrect since ΔH is greater than ΔU in this case. - **Option 3**: "ΔH is always less than ΔU" - This is incorrect as ΔH can be equal to or greater than ΔU depending on the number of moles. - **Option 4**: "ΔH is less than ΔU only if the number of moles of product is less than that of moles of reactant" - This is correct, as we derived that ΔH < ΔU when Δn_g < 0. ### Conclusion The correct answer is **Option 4**: "ΔH is less than ΔU only if the number of moles of product is less than that of moles of reactant." ---
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