`(CH_(3))_(3) CMgCl` on reaction with `D_(2)O` produces

Options

A. `(CH_(3))_(3)CD`
B. `(CH_(3))_(3)OD`
C. `(CD_(3))_(3)CD`
D. `(CD_(3))_(3)OD`

Answer

To determine the product of the reaction between (CH₃)₃CMgCl (a Grignard reagent) and D₂O (heavy water), we can follow these steps:

### Step 1: Identify the Reactants
The reactants are:
- (CH₃)₃CMgCl (a Grignard reagent)
- D₂O (heavy water)

### Step 2: Understand the Nature of Grignard Reagents
Grignard reagents are highly reactive organomagnesium compounds. In (CH₃)₃CMgCl, the carbon atom (C) bonded to magnesium (Mg) has a partial negative charge due to the electronegativity difference between carbon and magnesium. Thus, we can represent it as:
- C δ- (carbon with a partial negative charge)
- Mg δ+ (magnesium with a partial positive charge)

### Step 3: Ionization of D₂O
D₂O can ionize to produce:
- D⁺ (deuterium ion)
- OD⁻ (deuteroxide ion)

### Step 4: Reaction Mechanism
In the reaction, the carbon atom (C) of the Grignard reagent will attack the D⁺ ion from D₂O, while the magnesium ion (Mg) will bond with the OD⁻ ion.

### Step 5: Write the Products
The products of the reaction will be:
- The carbon will bond with D, forming (CH₃)₃C-D.
- The magnesium will bond with the deuteroxide ion, forming Mg(OD)Cl.

Thus, the overall product can be represented as:
- (CH₃)₃C-D + Mg(OD)Cl

### Final Product
The main product of the reaction is:
- (CH₃)₃C-D (tert-butyl deuteride)
- Mg(OD)Cl (magnesium deuteroxide chloride)

### Summary of the Reaction
The reaction of (CH₃)₃CMgCl with D₂O produces:
- (CH₃)₃C-D (tert-butyl deuteride)
- Mg(OD)Cl

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