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Ice starts forming in lake with water at...

Ice starts forming in lake with water at `0^(@)C` and when the atmospheric temperature is `-10^(@)C`. If the time taken for `1 cm` of ice be `7` hours. Find the time taken for the thickness of ice to change from `1 cm` to `2 cm`

A

7 hours

B

14 hours

C

10.5 hours

D

21 hours

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the time taken for the thickness of ice to change from 1 cm to 2 cm, we can follow these steps: ### Step 1: Understand the relationship between thickness and time The thickness of ice formed is related to the time taken for its formation. The relationship can be expressed as: \[ t \propto x^2 \] where \( t \) is the time taken and \( x \) is the thickness of the ice. ### Step 2: Establish the constant of proportionality From the relationship above, we can express the time taken to form a thickness \( x \) as: \[ t = \frac{x^2}{2c} \] where \( c \) is a constant that depends on the material properties and conditions. ### Step 3: Calculate the time for 1 cm thickness Given that the time taken to form 1 cm (0.01 m) of ice is 7 hours, we can substitute \( x = 1 \) cm into the equation: \[ t_1 = \frac{1^2}{2c} = 7 \text{ hours} \] This implies: \[ \frac{1}{2c} = 7 \implies 2c = \frac{1}{7} \implies c = \frac{1}{14} \] ### Step 4: Calculate the time for 2 cm thickness Now, we can calculate the time taken to form 2 cm (0.02 m) of ice: \[ t_2 = \frac{2^2}{2c} = \frac{4}{2c} \] Substituting \( c = \frac{1}{14} \): \[ t_2 = \frac{4}{2 \times \frac{1}{14}} = \frac{4 \times 14}{2} = 28 \text{ hours} \] ### Step 5: Find the time difference To find the time taken for the thickness of ice to change from 1 cm to 2 cm, we calculate: \[ \Delta t = t_2 - t_1 = 28 \text{ hours} - 7 \text{ hours} = 21 \text{ hours} \] ### Final Answer The time taken for the thickness of ice to change from 1 cm to 2 cm is **21 hours**. ---
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