Home
Class 12
PHYSICS
In young's double-slit experiment, both ...

In young's double-slit experiment, both the slits produce equal intensities on a screen. A 100% transparent thin film of refractive index `mu = 1.5` is kept in front of one of the slits, due to which the intensity at the point O on the screen becomes 75% of its initial value. If the wavelength of monochromatic light is 720 nm, then what is the minimum thickness (in nm) of the film?

Text Solution

Verified by Experts

The correct Answer is:
240
Promotional Banner

Similar Questions

Explore conceptually related problems

In YDSE, both slits produce equal intensities on the screen. A 100% transparent thin film is placed in front of one of the slits. Now, the intensity on the centre becomes 75% of the previous intensity. The wavelength of light is 6000Å and refractive index of glass is 1.5. Thus, minimum thickness of the glass slab is

A thin plastic of refractive index 1.6 is used to cover one of the slits of a double slit arrangement. The central point omn the screen is now occupied by what would have been the 7th bright fringe before the plastic was used. If the wavelength of light is 600 nm, what is the thickness ( in mu m ) of the plastic?

Young's double slit experiment is conducted in a liquid of refractive index mu_1 as shown in figure. A thin transparent slab of refractive index mu_2 is placed in front of the slit s_2 . The magnitude of optical path difference at 'O' is

In Young's double-slit experment, the frist maxima is observed at a fixed point P on the screen. Now, the screen is continously moved away from the plane of slits. The ratio of intensity at point P to the intensity at point O (center of the screen)

In Young's double-slit experment, the frist maxima is observed at a fixed point P on the screen. Now, the screen is continously moved away from the plane of slits. The ratio of intensity at point P to the intensity at point O (center of the screen)

In Young's double-slit experiment, let A and B be the two slit. A thin film of thickness t and refractive index mu is placed in front of A. Let beta = fringe width. Then the central maxima will shift

In the above problem, minimum value of t for which the intensity at point P on the screen exactly in front of the upper slit becomes maximum.

The figure shows a Young's double slit experimental setup. It is observed that when a thin transparent sheet of thickness t and refractive index mu is put front of one of the slits, the central maximum gets shifted by a distance equal to n fringe widths. If the wavelength of light used is lambda , t will be :

A thin glass plate of thickness t and refractive index mu is inserted between screen and one of the slits in a young's experiment. If the intensity at the centre of the screen is I, what was the intensity at the same point prior to the introduction of the sheet.

In Young's double slit experiment with light of wavelength lambda=600 nm , intensity of central fringe is I_(0) . Now one of the slit is covered by glass plate of refractive index 1.4 and thickness t= 5mum . The new intensity at the same point on screen will be :