Hydrogen peroxide oxidises thiosulphate ion to-

Options

A. `SO_(3)^(2-)`
B. `SO_(4)^(2-)`
C. `S_(4)O_(6)^(2-)`
D. `S`

Answer

To determine the product formed when hydrogen peroxide (H₂O₂) oxidizes thiosulphate ion (S₂O₃²⁻), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are hydrogen peroxide (H₂O₂) and thiosulphate ion (S₂O₃²⁻).

### Step 2: Understand the Reaction
Hydrogen peroxide acts as an oxidizing agent. This means it will facilitate the oxidation of thiosulphate ion. The thiosulphate ion will lose electrons and increase its oxidation state.

### Step 3: Determine the Oxidation State of Sulfur in Thiosulphate
In the thiosulphate ion (S₂O₃²⁻), we need to find the oxidation state of sulfur (S). The formula for calculating the oxidation state is:
\[ \text{Oxidation state of S} = x \]
For the thiosulphate ion:
\[ 2x + 3(-2) = -2 \]
\[ 2x - 6 = -2 \]
\[ 2x = 4 \]
\[ x = +2 \]
Thus, the oxidation state of sulfur in thiosulphate is +2.

### Step 4: Determine the Product of the Reaction
When thiosulphate is oxidized by hydrogen peroxide, it is converted to sulfate ion (SO₄²⁻). The oxidation state of sulfur in sulfate is +6.

### Step 5: Write the Overall Reaction
The overall reaction can be summarized as:
\[ \text{S}_2\text{O}_3^{2-} + \text{H}_2\text{O}_2 \rightarrow \text{SO}_4^{2-} + \text{H}_2\text{O} \]

### Step 6: Conclusion
The product formed when hydrogen peroxide oxidizes thiosulphate ion is sulfate ion (SO₄²⁻).

### Final Answer
**Hydrogen peroxide oxidizes thiosulphate ion to sulfate ion (SO₄²⁻).**

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