In the following reactions , products (X) and (Y) respectively are
`underset(("hot and conc"))(NaOH)+Cl_2rarr(X)+` side products
`underset(("dry"))(Ca(OH)_2)+Cl_2rarr(Y)+` side products

Options

A. `NaOCl and Ca(ClO_3)_2`
B. `NaClO_3 and CaOCl_2`
C. `NaOCl and Ca(OCl)_2`
D. `NaClO_3 and Ca(ClO_3)_2`

Answer

To solve the problem, we need to identify the products (X) and (Y) formed in the given reactions involving chlorine and sodium hydroxide (NaOH) as well as calcium hydroxide (Ca(OH)₂).

### Step-by-Step Solution:

1. **Identify the first reaction:**
The first reaction involves hot and concentrated sodium hydroxide (NaOH) reacting with chlorine (Cl₂).

\[ \text{NaOH (hot and conc.)} + \text{Cl}_2 \rightarrow X + \text{side products} \]

2. **Determine the product (X):**
When chlorine reacts with hot concentrated sodium hydroxide, the main product formed is sodium chlorate (NaClO₃). The side products typically include sodium chloride (NaCl) and water (H₂O).

The balanced equation for this reaction can be represented as:
\[ 3 \text{Cl}_2 + 6 \text{NaOH} \rightarrow 5 \text{NaCl} + \text{NaClO}_3 + 3 \text{H}_2O \]
Thus, the product (X) is:
\[ X = \text{NaClO}_3 \]

3. **Identify the second reaction:**
The second reaction involves dry calcium hydroxide (Ca(OH)₂) reacting with chlorine (Cl₂).

\[ \text{Ca(OH)}_2 \text{ (dry)} + \text{Cl}_2 \rightarrow Y + \text{side products} \]

4. **Determine the product (Y):**
When dry calcium hydroxide reacts with chlorine, the main product formed is calcium hypochlorite (Ca(OCl)₂), commonly known as bleaching powder. The side product is typically water (H₂O).

The balanced equation for this reaction can be represented as:
\[ \text{Ca(OH)}_2 + \text{Cl}_2 \rightarrow \text{Ca(OCl)}_2 + \text{H}_2O \]
Thus, the product (Y) is:
\[ Y = \text{Ca(OCl)}_2 \]

5. **Final Answer:**
Therefore, the products of the reactions are:
- \( X = \text{NaClO}_3 \)
- \( Y = \text{Ca(OCl)}_2 \)