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Radiation of wavelength lambda, is incid...

Radiation of wavelength `lambda`, is incident on a photocell. The fastest emitted electron has speed v. If the wavelength is changed to `(3lambda)/(4)`, the speed of the fastest emitted electron will be :

A

`=v(4/3)^(1/2)`

B

`=v(3/4)^(1/2)`

C

`gtv(4/3)^(1/2)`

D

`ltv(4/3)^(1/2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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