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The dissociation equilibrium of a gas AB...

The dissociation equilibrium of a gas `AB_2` can be represented as, `2AB_2(g) hArr 2AB (g) +B_2(g)`. The degree of disssociation is 'x' and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant `k_p` and total pressure P is

A

`(2K_P//P)^(1/2)`

B

`K_P//P`

C

`2K_P//P`

D

`(2K_P//P)^(1/3)`

Text Solution

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The correct Answer is:
D
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