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Let Z is be the set of integers , if A={...

Let Z is be the set of integers , if `A={"x"inZ:|x-3|^((x^2-5x+6))=1} and B{x in Z : 10 lt3x+1lt 22}`, then the number of subsets of the set `AxxB` is

A

`2^6`

B

`2^8`

C

`2^15`

D

`2^9`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the sets A and B and then determine the number of subsets of the Cartesian product A × B. Let's break it down step by step. ### Step 1: Determine the Set A We have the set defined as: \[ A = \{ x \in \mathbb{Z} : |x - 3|^{(x^2 - 5x + 6)} = 1 \} \] To analyze this, we can break it down into cases based on the properties of exponents and absolute values. 1. **Case 1:** \( |x - 3| = 1 \) - This gives us two equations: - \( x - 3 = 1 \) → \( x = 4 \) - \( x - 3 = -1 \) → \( x = 2 \) 2. **Case 2:** \( x^2 - 5x + 6 = 0 \) - Factoring gives us: \[ (x - 2)(x - 3) = 0 \] - This results in: - \( x = 2 \) - \( x = 3 \) (but we will discard this since it leads to zero in the exponent) Since \( |x - 3|^{(x^2 - 5x + 6)} = 1 \) can also hold if the exponent is zero (which we already considered), we conclude that the valid integers for set A are: \[ A = \{2, 4\} \] ### Step 2: Determine the Set B The set B is defined as: \[ B = \{ x \in \mathbb{Z} : 10 < 3x + 1 < 22 \} \] We can solve this compound inequality: 1. From \( 3x + 1 > 10 \): \[ 3x > 9 \] \[ x > 3 \] 2. From \( 3x + 1 < 22 \): \[ 3x < 21 \] \[ x < 7 \] Combining these results, we find: \[ 3 < x < 7 \] The integers satisfying this condition are: \[ B = \{4, 5, 6\} \] ### Step 3: Calculate the Number of Elements in A and B - The number of elements in set A: \[ |A| = 2 \] - The number of elements in set B: \[ |B| = 3 \] ### Step 4: Calculate the Number of Elements in A × B The number of elements in the Cartesian product \( A \times B \) is given by: \[ |A \times B| = |A| \times |B| = 2 \times 3 = 6 \] ### Step 5: Calculate the Number of Subsets of A × B The number of subsets of a set with \( n \) elements is given by \( 2^n \). Therefore, the number of subsets of \( A \times B \) is: \[ \text{Number of subsets} = 2^{|A \times B|} = 2^6 = 64 \] ### Final Answer The number of subsets of the set \( A \times B \) is \( 64 \). ---
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