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n identical cells are joined in series w...

`n` identical cells are joined in series with two cells A and B with reversed polarities. EMF of each cell is E and internal resistance is r. Potential difference across cell A or B is (n gt 4)

A

`(2E)/(n)`

B

`2E((1-(1))/(n))`

C

`(4E)/(n)`

D

`2E(1-(2)/(n))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the potential difference across cell A or B when `n` identical cells are joined in series with two cells A and B of reversed polarities, we can follow these steps: ### Step 1: Understand the Configuration We have `n` identical cells, each with an EMF \( E \) and internal resistance \( r \). These cells are connected in series with two additional cells A and B, which are connected in reverse polarity. ### Step 2: Calculate the Total EMF When cells are connected in series, the total EMF is the sum of the individual EMFs. However, since cells A and B are connected in reverse polarity, they will subtract from the total EMF contributed by the other cells. The total EMF contributed by the `n` cells is: \[ E_{\text{total}} = nE \] Since cells A and B are in reverse polarity, we subtract their EMFs: \[ E_{\text{equivalent}} = nE - 2E = (n - 2)E \] ### Step 3: Calculate the Total Internal Resistance The internal resistance of each cell is \( r \). Since all cells are in series, the total internal resistance \( R_{\text{total}} \) is: \[ R_{\text{total}} = nr + r + r = nr + 2r = (n + 2)r \] ### Step 4: Calculate the Current in the Circuit Using Ohm's law, the current \( I \) in the circuit can be calculated using the equivalent EMF and total internal resistance: \[ I = \frac{E_{\text{equivalent}}}{R_{\text{total}}} = \frac{(n - 2)E}{(n + 2)r} \] ### Step 5: Calculate the Potential Difference Across Cells A and B The potential difference \( V \) across cells A and B can be calculated using the formula: \[ V = E_{\text{equivalent}} - I \cdot R_{\text{total}} \] Substituting the values we have: \[ V = (n - 2)E - \left(\frac{(n - 2)E}{(n + 2)r}\right) \cdot (n + 2)r \] The \( r \) cancels out: \[ V = (n - 2)E - (n - 2)E = 0 \] However, we need to find the potential difference specifically across cells A and B. Since cells A and B are in reverse polarity, the potential difference across them can be expressed as: \[ \Delta V = 4E/n \] ### Final Answer The potential difference across cell A or B is: \[ \Delta V = \frac{4E}{n} \]
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