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The total number of cyclic isomers of fo...

The total number of cyclic isomers of formula `C_(6)H_(12)` is/are

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To determine the total number of cyclic isomers for the molecular formula \( C_6H_{12} \), we can follow these steps: ### Step 1: Calculate the Degree of Unsaturation (DU) The degree of unsaturation (DU) can be calculated using the formula: \[ \text{DU} = \frac{(2C + 2 - H)}{2} \] For \( C_6H_{12} \): - \( C = 6 \) - \( H = 12 \) Substituting these values into the formula: \[ \text{DU} = \frac{(2 \times 6 + 2 - 12)}{2} = \frac{(12 + 2 - 12)}{2} = \frac{2}{2} = 1 \] This indicates that the compound can either have one double bond or be a cyclic compound. ### Step 2: Identify Possible Cyclic Structures Since we are looking for cyclic isomers, we can consider different cyclic structures that can be formed with 6 carbon atoms. 1. **Cyclohexane**: This is the simplest cyclic structure. 2. **Cyclopentane with a methyl group**: This can have multiple isomers based on the position of the methyl group. 3. **Cyclobutane with ethyl or methyl groups**: We can have cyclobutane with various substituents. 4. **Cyclopropane with different substituents**: This can include various arrangements of methyl and ethyl groups. ### Step 3: Count the Isomers Now we will count the distinct cyclic isomers: 1. **Cyclohexane**: 1 isomer. 2. **Cyclopentane with 1 methyl group**: 1 isomer (methyl at any position is the same due to symmetry). 3. **Cyclobutane with 1 ethyl group**: 1 isomer. 4. **Cyclobutane with 2 methyl groups**: 2 isomers (1,1-dimethylcyclobutane and 1,2-dimethylcyclobutane). 5. **Cyclobutane with 1 methyl and 1 ethyl group**: 1 isomer. 6. **Cyclopropane with 1 ethyl group and 1 methyl group**: 3 isomers (1-ethyl-2-methylcyclopropane, 1,1-dimethylcyclopropane, etc.). 7. **Cyclopropane with 3 methyl groups**: 1 isomer (1,1,2-trimethylcyclopropane). Adding these together gives: - Cyclohexane: 1 - Cyclopentane: 1 - Cyclobutane: 4 (1 ethyl, 2 dimethyl, 1 methyl-ethyl) - Cyclopropane: 5 (3 methyl, 1 ethyl, 1 dimethyl) Total = \( 1 + 1 + 4 + 5 = 11 \) ### Final Answer The total number of cyclic isomers of \( C_6H_{12} \) is **11**. ---
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