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If `a_(1), a_(2), a_(3)` are in arithmetic progression and d is the common diference, then `tan^(-1)((d)/(1+a_(1)a_(2)))+tan^(-1)((d)/(1+a_(2)a_(3)))=`

A

`tan^(-1)((2d)/(1+a_(1)a_(3)))`

B

`tan^(-1)((d)/(1+a_(1)a_(3)))`

C

`tan^(-1)((2d)/(1+a_(2)a_(3)))`

D

`tan^(-1)((2)/(1-a_(1)a_(3)))`

Text Solution

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The correct Answer is:
A
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