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Identify the correct statement :...

Identify the correct statement :

A

0.1 M NaCl and 0.1 M glucose solution are isotonic

B

0.1 M NaCl and 0.3 M glucose solution are isotonic.

C

The boiling point of 0.1 m aqueous urea solution is less than 0.1 m aqueous KCl solution.

D

The freezing point of 0.1 m glucose solution is less than 0.1 m KCl solution.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question of identifying the correct statement among the given options, we will analyze each statement step by step. ### Step 1: Understanding Isotonic Solutions Isotonic solutions have the same osmotic pressure. The osmotic pressure (π) can be calculated using the formula: \[ \pi = iCRT \] where: - \( i \) = van 't Hoff factor (number of particles the solute dissociates into) - \( C \) = concentration of the solution - \( R \) = gas constant - \( T \) = temperature (in Kelvin) ### Step 2: Analyzing the First Statement **Statement 1:** "0.1 molar NaCl solution and 0.1 molar glucose solution are isotonic." - For NaCl: - \( i = 2 \) (Na⁺ and Cl⁻) - \( C = 0.1 \) - \( \pi_{NaCl} = 2 \times 0.1 \times R \times T = 0.2RT \) - For glucose: - \( i = 1 \) (does not dissociate) - \( C = 0.1 \) - \( \pi_{glucose} = 1 \times 0.1 \times R \times T = 0.1RT \) Since \( \pi_{NaCl} \neq \pi_{glucose} \), they are not isotonic. **This statement is incorrect.** ### Step 3: Analyzing the Second Statement **Statement 2:** "0.1 molar NaCl and 0.3 molar glucose solution is isotonic." - For NaCl: - \( \pi_{NaCl} = 2 \times 0.1 \times R \times T = 0.2RT \) - For glucose: - \( i = 1 \) - \( C = 0.3 \) - \( \pi_{glucose} = 1 \times 0.3 \times R \times T = 0.3RT \) Since \( \pi_{NaCl} \neq \pi_{glucose} \), they are not isotonic. **This statement is incorrect.** ### Step 4: Analyzing the Third Statement **Statement 3:** "The boiling point of 0.1 molal aqueous urea solution is less than 0.1 molal aqueous KCl solution." - For urea: - \( i = 1 \) - \( \Delta T_b = i \cdot K_b \cdot m = 1 \cdot K_b \cdot 0.1 = 0.1K_b \) - For KCl: - \( i = 2 \) - \( \Delta T_b = 2 \cdot K_b \cdot 0.1 = 0.2K_b \) Since \( \Delta T_b(KCl) > \Delta T_b(Urea) \), the boiling point of urea is indeed less than that of KCl. **This statement is correct.** ### Step 5: Analyzing the Fourth Statement **Statement 4:** "The freezing point of 0.1 molar glucose solution is less than 0.1 molar KCl solution." - For glucose: - \( i = 1 \) - \( \Delta T_f = i \cdot K_f \cdot m = 1 \cdot K_f \cdot 0.1 = 0.1K_f \) - For KCl: - \( i = 2 \) - \( \Delta T_f = 2 \cdot K_f \cdot 0.1 = 0.2K_f \) Since \( \Delta T_f(KCl) > \Delta T_f(glucose) \), the freezing point of glucose is actually greater than that of KCl. **This statement is incorrect.** ### Conclusion The only correct statement among the options provided is: **The boiling point of 0.1 molal aqueous urea solution is less than 0.1 molal aqueous KCl solution.** ---
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