Home
Class 12
CHEMISTRY
Heating mixture of Cu(2)O and Cu(2)S wil...

Heating mixture of `Cu_(2)O` and `Cu_(2)S` will give

A

`Cu+SO_(2)`

B

`Cu+SO_(3)`

C

`CuO+CuS`

D

`Cu_(2)SO_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the heating of a mixture of \( \text{Cu}_2\text{O} \) and \( \text{Cu}_2\text{S} \), we can follow these steps: ### Step 1: Identify the Reactants The reactants in this reaction are: - \( \text{Cu}_2\text{O} \) (Copper(I) oxide) - \( \text{Cu}_2\text{S} \) (Copper(I) sulfide) ### Step 2: Write the Reaction When \( \text{Cu}_2\text{O} \) is heated with \( \text{Cu}_2\text{S} \), they undergo a chemical reaction. The reaction can be represented as: \[ \text{Cu}_2\text{O} + \text{Cu}_2\text{S} \rightarrow \text{Cu} + \text{SO}_2 \] ### Step 3: Balance the Reaction To ensure that the reaction is balanced, we need to have the same number of each type of atom on both sides of the equation. Balancing the equation gives us: \[ 2 \text{Cu}_2\text{O} + 6 \text{Cu}_2\text{S} \rightarrow 8 \text{Cu} + 2 \text{SO}_2 \] ### Step 4: Identify the Products From the balanced equation, we can see that the products of the reaction are: - Copper (Cu) - Sulfur dioxide (\( \text{SO}_2 \)) ### Conclusion Thus, when a mixture of \( \text{Cu}_2\text{O} \) and \( \text{Cu}_2\text{S} \) is heated, it produces copper metal and sulfur dioxide gas. Therefore, the answer is: \[ \text{Cu} + \text{SO}_2 \] ### Final Answer The correct answer is \( \text{Cu} + \text{SO}_2 \), which corresponds to option number A. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

On heating a mixture of Cu_(2)O and Cu_(2)S , we get

What happens when (a) ZnCO_(3) is heated in the absence of oxygen? (b) a mixture of Cu_(2)O" and "Cu_(2)S is heated?

When a equimolar mixture of Cu_(2) S and CuS is tirated with Ba(MnO_(4))_(2) in acidic medium, the final products cintain Cu^(2+) , So_(2) and Mn^(2+) . If the mol. Mass of Cu_(2) S, CuS and Ba(MnO_(4))_(2) are M_(1) , M_(2) and M_(3) respectively then :

During the quation analysis of a mixture containing Cu^(2+) and Zn^(2+) ions H_(2)S gas is passed therough an acidified solution containing these ions in order to test Cu^(2+) alone explane

What type of the reduction method does the following reaction show (Bessemer converter reaction of metallurgy of copper) ? 2Cu_(2)O+Cu_(2)Soverset(Delta)(to)6Cu+SO_(2)

The standard reduction potentials of Cu^(2+)|Cu and Cu^(2+)|Cu^(o+) are 0.337V and 0.153V , respectively. The standard electrode potential fo Cu^(o+)|Cu half cell in Volts is

The standard reduction potentials of Cu^(2+)|Cu and Cu^(2+)|Cu^(o+) are 0.337V and 0.153V , respectively. The standard electrode potential fo Cu^(o+)|Cu half cell is

Actylene reacts with ammonical Cu_(2)Cl_(2) to give precipitate of

A mixture of CuS (molecular weight = M_(1) ) and Cu_(2)S (molecular weight =M_(2) ) is oxidised by KMnO_(4) (molecular weight =M_(3) ) in acidic medium, where the product obtained are Cu^(2+),Mn^(2+) and SO_(2) . Find the equivalent weight of CuS, Cu_(2)S and KMnO_(4) respectively.

Justify that the reaction is a redox reaction. " "2Cu_(2)O(s)+Cu_(2)S(s) rarr 6Cu(s)+SO_(2)(g)