A uniform circular loop of radius a and resistance R is pulled at a constant velocity v out of a region of a uniform plane of the loop and the velocity are both perpendicular to B. Then the electrical power in the circular loop at the instant when the arc (of the circular loop) outside the region of magnetic field subtends an angle `(pi)/(3)` at the centre of the loop is

Options

A. `(B^(2)a^(2)v^(2))/(R)`
B. `(2B^(2)a^(2)v^(2))/(R)`
C. `(B^(2)a^(2)v^(2))/(2R)`
D. none of these

Answer

A