An athlete, initially at rest, takes 2 s to reach his maximum speed of `"36 km h"^(-1)`. The magnitude of his average accleration (in`ms^(-2)`) is

Answer

To find the magnitude of the average acceleration of the athlete, we can follow these steps:

### Step 1: Identify the initial and final velocities
- The athlete starts from rest, so the initial velocity (u) is:
\[ u = 0 \, \text{m/s} \]
- The final velocity (v) is given as 36 km/h.

### Step 2: Convert the final velocity from km/h to m/s
- To convert km/h to m/s, we use the conversion factor:
\[ 1 \, \text{km/h} = \frac{5}{18} \, \text{m/s} \]
- Therefore, we convert 36 km/h to m/s:
\[ v = 36 \times \frac{5}{18} = 10 \, \text{m/s} \]

### Step 3: Calculate the time taken
- The time taken (t) to reach the maximum speed is given as:
\[ t = 2 \, \text{s} \]

### Step 4: Use the formula for average acceleration
- The formula for average acceleration (a) is:
\[ a = \frac{v - u}{t} \]
- Substituting the values we have:
\[ a = \frac{10 \, \text{m/s} - 0 \, \text{m/s}}{2 \, \text{s}} = \frac{10 \, \text{m/s}}{2 \, \text{s}} = 5 \, \text{m/s}^2 \]

### Final Answer
- The magnitude of the average acceleration is:
\[ a = 5 \, \text{m/s}^2 \]

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