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Equal masses of methane and ethane have ...

Equal masses of methane and ethane have their total translational kinetic energy in the ratio `3:1`, then their temperature are in the ratio is

A

`5:8`

B

`45:8`

C

`15:8`

D

`8:5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of temperatures of methane and ethane given that their translational kinetic energy is in the ratio of 3:1. ### Step-by-Step Solution: 1. **Understanding the Kinetic Energy Formula**: The translational kinetic energy (KE) of a gas is given by the formula: \[ KE = \frac{3}{2} nRT \] where \( n \) is the number of moles, \( R \) is the universal gas constant, and \( T \) is the temperature. 2. **Setting Up the Equations**: Let: - \( KE_M \) = translational kinetic energy of methane - \( KE_E \) = translational kinetic energy of ethane According to the problem, we have: \[ \frac{KE_M}{KE_E} = \frac{3}{1} \] Using the kinetic energy formula for both gases, we can write: \[ \frac{KE_M}{KE_E} = \frac{\frac{3}{2} n_M R T_M}{\frac{3}{2} n_E R T_E} \] This simplifies to: \[ \frac{n_M T_M}{n_E T_E} = 3 \] 3. **Finding the Number of Moles**: The number of moles \( n \) can be calculated using the formula: \[ n = \frac{W}{M} \] where \( W \) is the weight and \( M \) is the molar mass. For methane (CH₄): - Molar mass \( M_M = 16 \, \text{g/mol} \) - Number of moles of methane: \[ n_M = \frac{W_M}{16} \] For ethane (C₂H₆): - Molar mass \( M_E = 30 \, \text{g/mol} \) - Number of moles of ethane: \[ n_E = \frac{W_E}{30} \] 4. **Substituting into the Ratio**: Since the problem states that equal masses of methane and ethane are used, we have \( W_M = W_E = W \). Thus: \[ n_M = \frac{W}{16} \quad \text{and} \quad n_E = \frac{W}{30} \] Now substituting these values into the kinetic energy ratio: \[ \frac{\frac{W}{16} T_M}{\frac{W}{30} T_E} = 3 \] The \( W \) cancels out: \[ \frac{30 T_M}{16 T_E} = 3 \] 5. **Solving for the Temperature Ratio**: Rearranging gives: \[ 30 T_M = 48 T_E \] Thus: \[ \frac{T_M}{T_E} = \frac{48}{30} = \frac{8}{5} \] ### Final Answer: The ratio of temperatures \( T_M : T_E \) is: \[ \boxed{8 : 5} \]
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