Find out the compounds that will disproportionate in their aqueous solution.
`(I)ClO_(4)^(-)overst(+0.36V)rarr ClO_(3)^(-) overset(+0.33V)rarr ClO_(2) overset(+0.66V)rarr OC l^(-)overset(+0.40V)rarr(1)/(2)Cl_(2)overset(+1.36)rarr Cl^(-)`
`(II)MnO_(4)^(-)overset(+0.56)rarrMnO_(4)^(2-)overset(+2.22V)rarrMnO_(2)overset(+0.95V)rarrMn^(3+)overset(+1.55)rarrMn^(2+)overset((-0.19)V)rarrMn`

Options

A.
B.
C.
D.

Answer

To determine which compounds will disproportionate in their aqueous solution, we need to analyze the given half-reactions and their standard reduction potentials. Disproportionation occurs when a species can simultaneously be oxidized and reduced, which is indicated by the reduction potentials of the half-reactions.

### Step-by-Step Solution:

1. **Identify the Half-Reactions and Their Potentials**:
- For the first set:
- \( \text{ClO}_4^{-} \) to \( \text{ClO}_3^{-} \) (E = +0.36 V)
- \( \text{ClO}_3^{-} \) to \( \text{ClO}_2 \) (E = +0.33 V)
- \( \text{ClO}_2 \) to \( \text{OCl}^{-} \) (E = +0.66 V)
- \( \text{OCl}^{-} \) to \( \frac{1}{2} \text{Cl}_2 \) (E = +1.36 V)
- \( \frac{1}{2} \text{Cl}_2 \) to \( \text{Cl}^{-} \) (E = +0.40 V)

- For the second set:
- \( \text{MnO}_4^{-} \) to \( \text{MnO}_4^{2-} \) (E = +0.56 V)
- \( \text{MnO}_4^{2-} \) to \( \text{MnO}_2 \) (E = +2.22 V)
- \( \text{MnO}_2 \) to \( \text{Mn}^{3+} \) (E = +0.95 V)
- \( \text{Mn}^{3+} \) to \( \text{Mn}^{2+} \) (E = +1.55 V)
- \( \text{Mn}^{2+} \) to \( \text{Mn} \) (E = -0.19 V)

2. **Check for Disproportionation**:
- A species will disproportionate if the reduction potential of the product formed by reduction is greater than that of the reactant.

- **For Chlorine Compounds**:
- **ClO2**:
- Reduction potential from ClO2 to ClO3 is +0.33 V (left side).
- Reduction potential from ClO2 to OCl- is +0.66 V (right side).
- Since +0.66 V > +0.33 V, ClO2 will disproportionate.

- **Cl2**:
- Reduction potential from Cl2 to Cl- is +0.40 V (right side).
- Reduction potential from Cl2 to ClO4- is +1.36 V (left side).
- Since +1.36 V > +0.40 V, Cl2 will also disproportionate.

- **For Manganese Compounds**:
- **MnO4^{2-}**:
- Reduction potential from MnO4^{2-} to MnO4^{-} is +0.56 V (left side).
- Reduction potential from MnO4^{2-} to MnO2 is +2.22 V (right side).
- Since +2.22 V > +0.56 V, MnO4^{2-} will disproportionate.

- **Mn^{3+}**:
- Reduction potential from Mn^{3+} to Mn^{2+} is +1.55 V (right side).
- Reduction potential from Mn^{3+} to MnO2 is +0.95 V (left side).
- Since +1.55 V > +0.95 V, Mn^{3+} will also disproportionate.

3. **Conclusion**:
- The compounds that will disproportionate in their aqueous solution are:
- ClO2
- Cl2
- MnO4^{2-}
- Mn^{3+}

### Final Answer:
The compounds that will disproportionate in their aqueous solution are ClO2, Cl2, MnO4^{2-}, and Mn^{3+}.