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AlCl(3) forms dimer in vapour phase but ...

`AlCl_(3)` forms dimer in vapour phase but `BCl_(3)` does not because

A

In Al there are vacant d orbitals in which it accommodates lone pair from chlorine atoms

B

In `BCl_(3)` there is back bonding

C

There is hyrogen bonding in between two `AlCl_(3)` molecules in vapour phase

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To understand why AlCl₃ forms a dimer in the vapor phase while BCl₃ does not, we can analyze the electronic configurations and bonding characteristics of both compounds step by step. ### Step 1: Analyze the Electronic Configuration - **Aluminum (Al)** has the electronic configuration: \[ 1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^1 \] - **Boron (B)** has the electronic configuration: \[ 1s^2 \, 2s^2 \, 2p^1 \] ### Step 2: Identify the Valence Shells - Aluminum is in the third period and has access to the 3s, 3p, and 3d orbitals. - Boron is in the second period and only has access to the 2s and 2p orbitals. It does not have d orbitals available. ### Step 3: Dimer Formation in AlCl₃ - In AlCl₃, the aluminum atom can utilize its vacant 3d orbitals to accommodate the lone pairs from the chlorine atoms. This allows for the formation of a dimer (Al₂Cl₆) through coordinate covalent bonding. ### Step 4: Lack of Dimer Formation in BCl₃ - In BCl₃, there are no vacant d orbitals available for bonding with the lone pairs from chlorine. As a result, BCl₃ cannot form dimers. Instead, it exists as discrete BCl₃ molecules. ### Step 5: Evaluate the Options - **Option A**: "In Al there are vacant d-orbitals in which it accommodates lone pair from chlorine atoms." - This is true. - **Option B**: "In BCl₃ there is back bonding." - This is not applicable as BCl₃ does not have d orbitals for back bonding. - **Option C**: "There is hydrogen bonding in between AlCl₃ molecules in vapor phase." - This is false, as neither molecule contains hydrogen. - **Option D**: "None of these." - Since Option A is correct, this cannot be the answer. ### Conclusion The correct answer is **Option A**: "In Al there are vacant d-orbitals in which it accommodates lone pair from chlorine atoms." ---
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