Home
Class 12
PHYSICS
A nucleus of mass M+Deltam is at rest an...

A nucleus of mass `M+Deltam` is at rest and decays into two daughter nuclei of equal mass `(M)/(2)` each. Speed of light is c.
The speed of daughter nuclei is

A

`c(Delta)/(M+Deltam)`

B

`c sqrt((2Deltam)/(M))`

C

`c sqrt((Deltam)/(M))`

D

`c sqrt((Deltam)/(M+Deltam))`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A nucleus of mass M + Deltam is at rest and decays into two daughter nuclei of equal mass M/2 each. Speed of light is C. The speed of deughter nuclei is :-

A nuclear of mass M +deltam is at rest and decay into two daughter nuclei of equal mass (M)/(2) each speed is c The binding energy per nucleon for the nucleus is E_(1) and that for the daugther nuclei is E_(2) Then

A particle of mass 3m at rest decays into two particles of masses m and 2m having non-zero velocities. The ratio of the de Broglie wavelengths of the particles ((lamda_1)/(lamda_2)) is

A particle of mass 4m at rest decays into two particles of masses m and 3m having non-zero velocities. The ratio of the de Broglie wavelengths of the particles 1 and 2 is

A radioactive nucleus of mass number A, initially at rest, emits an alpha- particle with a speed v. What will be the recoil speed of the daughter nucleus ?

A praticle of mass M at rest decays into two particle of masses m_1 and m_2 , having non-zero velocities. The ratio of the de Broglie wavelength of the particles (lamda_1)/(lamda_2) is

The mass of a nucleus ._(Z)^(A)X is less that the sum of the masses of (A-Z) number of neutrons and Z number of protons in the nucleus.The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of masses m_(1) and m_(2) only if (m_(1)+m_(2)) lt M . Also two light nuclei of masses m_(3) and m_(4) can undergo complete fusion and form a heavy nucleus of mass M'. only if (m_(3)+m_(4)) gt M' . The masses of some neutral atoms are given in the table below: |{:(._(1)^(1)H ,1.007825u , ._(1)^(2)H,2.014102u,._(1)^(3)H,3.016050u,._(2)^(4)He,4.002603u),(._(3)^(6)Li,6.015123u,._(3)^(7)Li,7.016004u,._(30)^(70)Zn,69.925325u, ._(34)^(82)Se,81.916709u),(._(64)^(152)Gd,151.91980u,._(82)^(206)Pb,205.974455u,._(83)^(209)Bi,208.980388u,._(84)^(210)Po,209.982876u):}| The correct statement is:

A nucleus of mass 220 amu in the free state decays to emit an alpha -particle . Kinetic energy of the alpha -particle emitted is 5.4 MeV. The recoil energy of the daughter nucleus is

A nucleus of mass 218 amu is in free state decays to emit an alpha -particle. Kinetic energy of alpha -particle emitted is 6.7Mev. The recoil energy in (MeV) emitted by the daughter nucleus is

Suppose, the daughter nucleus in a nuclear decay is itself radioactive. Let lambda_p and lambda_d be the decay constants of the parent and the daughter nuclei. Also, let N_p and N_d be the number of parent and daughter nuclei at time t . Find the condition for which the number of daughter nuclei becomes constant.