Home
Class 12
CHEMISTRY
A compound (X) of molecular formula C(3)...

A compound (X) of molecular formula `C_(3)H_(6)O` forms bisulphate complex, gives iodoform test but does not reduce Tollens reagent. (X) on reaction with `CH_(3)MgBr//H_(3)O^(+)` gives a compound (Y) that cannot

A

give red colour with Cerium Ammonium Nitrate (CAN)

B

give white turbidity immediately with Lucas reagent

C

give iodoform test

D

be dehydrated to alkene on reaction with heated Cu

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the information given about the compound (X) with the molecular formula \( C_3H_6O \). ### Step 1: Identify the structure of compound (X) The molecular formula \( C_3H_6O \) suggests that (X) could be either an aldehyde or a ketone. - Aldehyde structure: \( CH_3CH_2CHO \) - Ketone structure: \( CH_3C(=O)CH_3 \) ### Step 2: Analyze the chemical tests 1. **Iodoform Test**: This test is positive for methyl ketones (compounds with the structure \( RCOCH_3 \)). Therefore, if (X) gives a positive iodoform test, it must be a ketone. 2. **Tollens' Reagent**: Aldehydes reduce Tollens' reagent, while ketones do not. Since (X) does not reduce Tollens' reagent, it cannot be an aldehyde. ### Conclusion about (X) Since (X) gives a positive iodoform test and does not reduce Tollens' reagent, (X) must be the ketone \( CH_3C(=O)CH_3 \) (acetone). ### Step 3: Reaction with Grignard Reagent When (X) reacts with \( CH_3MgBr \) followed by hydrolysis with \( H_3O^+ \), it produces a tertiary alcohol (Y). The reaction can be outlined as follows: 1. The Grignard reagent \( CH_3MgBr \) attacks the carbonyl carbon of the ketone, forming an alkoxide intermediate. 2. Upon hydrolysis, this intermediate is converted to the corresponding tertiary alcohol. The structure of (Y) will be: \[ Y = CH_3C(OH)(CH_3)CH_3 \] (tert-butyl alcohol). ### Step 4: Analyze the properties of compound (Y) Now we need to evaluate the options given in the question about compound (Y): 1. **Red color with cerium ammonium nitrate**: True, as tertiary alcohols can form colored complexes with cerium salts. 2. **White turbidity with Lucas reagent**: True, as tertiary alcohols react quickly with Lucas reagent to form alkyl chlorides. 3. **Gives iodoform test**: False, as iodoform test is not given by tertiary alcohols. 4. **Dehydrated to alkene on reaction with heated copper**: True, as tertiary alcohols can dehydrate to form alkenes under heating. ### Final Answer The compound (Y) cannot give the iodoform test.
Promotional Banner

Similar Questions

Explore conceptually related problems

Compound X with molecular formula C_(6)H_(10)O form a semicarbazone and give negative Tollen's and lodoform tests. Upon reduction

An organic compound of molecular formula C_(3)H_(6)O did not give a silver mirror with with Tollens' reagent but give an oxime with hydroxylamine. It may be

A compound (X) with a molecualr formula C_(5)H_(10)O gives a positive 2, 4-DNP test but a negative Tollens' test. On oxidation it gives a carboxylic acid (Y) with a molecular formula C_(3)H_(6)O_(2) . Potassium salt of (Y) undergoes Kolbe's reaction and gives a hydrocarbon (Z). (X), (Y) and (Z) respectively are

A compound (X) has the molecular formula C_3 H_7 NO . With Br_2 and KOH , (X) gives (Y) . (Y) responds to mustard oil reaction . (Y) upon treatment with HNO_2 evolves N_2 and gives an alcohol (Z) which gives iodoform test , (X) is likelty to be :

An organic compound 'X' having molecular formula C_(5)H_(10)O yield phenylhydrazone and gives negative response to the iodoform test and Tollens test . It produces n-pentane on reduction. 'X' could be

An organic compound 'X' having molecular formula C_(5)H_(10)O yield phenylhydrazone and gives negative response to the iodoform test and Tollens test . It produces n-pentane on reduction. 'X' could be

A compound (X) with the molecular formula C_(3)H_(8)O can be oxidized to another (Y) whose molecular formula is C_(3)H_(6)O_(2) The compound (X) may be

An aromatic compound X with molecular formula C_(9)H_(10)O gives following chemical tests: (i) Form 2,4-DNP derivative (ii) Reduces Tollen's reagent (iii) undergoes Cannizzaro's reaction (iv) On vigorous oxidation 1, 2-Benzene dicarboxylic acid is obtained The compound X is ,

An organic compound (X) with molecular formula C_(9)H_(10)O gives positive 2, 4-DNP and Tollens'tests. It undergoes Cannizzaro reaction and on vigorous oxidation it gives 1, 4-benzenedicarboxylic acid. Compound (X) is