Home
Class 12
MATHS
The perpendicular bisector of a line seg...

The perpendicular bisector of a line segment with end points (1, 2, 6) and `(-3, 6, 2)` passes through `(-6, 2, 4)` and has the equation of the form `(x+6)/(l)=(y-2)/(m)=(z-4)/(n)` (where `l gt0`), then the value of `lmn -(l+m+n)` equals to

A

`-3`

B

`-5`

C

`-7`

D

`-9`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of the perpendicular bisector of the line segment joining the points A(2,3)a n dB(6,-5)dot

The mid-point of the segment joining (3m, 6) and (-4, 3n) is (1, 2m, -1). Find the values of m and n.

The equations of bisectors of two lines L_1 & L_2 are 2x-16y-5=0 and 64x+ 8y+35=0 . lf the line L_1 passes through (-11, 4) , the equation of acute angle bisector of L_1 & L_2 is:

Find the equation of the plane through the points (2,2,1) and (9,3,6) and perpendicular to the plane 2x+6y+6z=1

Find the equation of the plane through the points (2,2,1) and (9,3,6) and perpendicular to the plane 2x+6y+6z=1

Find the equation of the plane through the points (2,2,1) and (9,3,6) and perpendicular to the plane 2x+6y+6z=1

Distance of the point P(x_2, y_2, z_2) from the line (x-x_1)/l=(y-y_1)/m=(z-z_1)/n , where l,m,n are the direction cosines of the line, is

theta_1 and theta_2 are the inclination of lines L_1 and L_2 with the x-axis. If L_1 and L_2 pass through P(x_1,y_1) , then the equation of one of the angle bisector of these lines is

Equation of plane passing through the points (2, 2, 1) (9, 3, 6) and perpendicular to the plane 2x+6y+6z-1=0 is

Lying in the plane x+y+z=6 is a line L passing through (1, 2, 3) and perpendicular to the line of intersection of planes x+y+z=6 and 2x-y+z=4 , then the equation of L is