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The power radiated by a black body is P ...

The power radiated by a black body is P and it radiates maximum energy at wavelength` lambda_(0)`.If the temperature of the black body is now changed, so that it radiates maximum energy at wavelength `(3)/(4) lambda_(0)`, the power radiated by it becomes nP.The value of n is

A

`(4)/(3)P_(0)`

B

`(16)/(9)P_(0)`

C

`(64)/(27)P_(0)`

D

`(256)/(81)P_(0)`

Text Solution

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The correct Answer is:
D
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