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The locus of the mid-point of the chords...

The locus of the mid-point of the chords of the hyperbola `x^(2)-y^(2)=4`, that touches the parabola `y^(2)=8x` is

A

`x^(2)(x-2)=y^(3)`

B

`y^(2)(x-2)=x^(3)`

C

`x^(3)(x-2)=y^(2)`

D

`y^(3)(x-2)=x^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the locus of the mid-point of the chords of the hyperbola \(x^2 - y^2 = 4\) that touch the parabola \(y^2 = 8x\), we can follow these steps: ### Step 1: Define the Midpoint Let the midpoint of the chord be \(P(h, k)\), where \(h\) and \(k\) are the coordinates of the midpoint. ### Step 2: Write the Equation of the Chord The equation of the chord of the hyperbola \(x^2 - y^2 = 4\) with midpoint \(P(h, k)\) can be expressed as: \[ x h - y k = h^2 - k^2 \] This represents the chord of the hyperbola that passes through the point \(P(h, k)\). ### Step 3: Rearranging the Equation Rearranging the equation gives: \[ k y = h x - (h^2 - k^2) \] This can be rewritten as: \[ y = \frac{h}{k} x - \frac{h^2 - k^2}{k} \] ### Step 4: Condition for Tangency Since this chord touches the parabola \(y^2 = 8x\), we need to apply the condition for tangency. For the line \(y = mx + c\) to be tangent to the parabola \(y^2 = 8x\), the discriminant of the resulting quadratic equation must be zero. Substituting \(y = \frac{h}{k} x - \frac{h^2 - k^2}{k}\) into \(y^2 = 8x\): \[ \left(\frac{h}{k} x - \frac{h^2 - k^2}{k}\right)^2 = 8x \] ### Step 5: Expanding and Rearranging Expanding the left-hand side: \[ \frac{h^2}{k^2} x^2 - 2\frac{h(h^2 - k^2)}{k^2} x + \frac{(h^2 - k^2)^2}{k^2} = 8x \] Rearranging gives: \[ \frac{h^2}{k^2} x^2 - \left(2\frac{h(h^2 - k^2)}{k^2} + 8\right)x + \frac{(h^2 - k^2)^2}{k^2} = 0 \] ### Step 6: Setting the Discriminant to Zero For tangency, the discriminant must be zero: \[ \left(2\frac{h(h^2 - k^2)}{k^2} + 8\right)^2 - 4\left(\frac{h^2}{k^2}\right)\left(\frac{(h^2 - k^2)^2}{k^2}\right) = 0 \] ### Step 7: Simplifying the Condition This leads to a relationship between \(h\) and \(k\). After simplifying, we can express \(k^2\) in terms of \(h\): \[ k^2(h - 2) = h^3 \] ### Step 8: Final Locus Equation This gives us the locus of the midpoints as: \[ k^2 = \frac{h^3}{h - 2} \] Substituting \(k = y\) and \(h = x\), we get: \[ y^2 = \frac{x^3}{x - 2} \] ### Final Result Thus, the locus of the midpoints of the chords of the hyperbola that touch the parabola is: \[ y^2 = \frac{x^3}{x - 2} \]
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