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The perimeter of a parallelogram whose s...

The perimeter of a parallelogram whose sides are represented by the lines `x+2y+3=0`,
`3x+4y-5=0,2x+4y+5=0 and 3x+4y-10=0` is equal to

A

`(5)/(2)+5sqrt5` units

B

`5+4sqrt5` units

C

`5+(5)/(2)sqrt5` units

D

`(5+5sqrt5)/(2)` units

Text Solution

AI Generated Solution

The correct Answer is:
To find the perimeter of the parallelogram formed by the given lines, we will follow these steps: ### Step 1: Identify the lines and their slopes The lines are: 1. \( x + 2y + 3 = 0 \) 2. \( 3x + 4y - 5 = 0 \) 3. \( 2x + 4y + 5 = 0 \) 4. \( 3x + 4y - 10 = 0 \) To determine if the lines are parallel, we need to find their slopes. For the line \( ax + by + c = 0 \), the slope \( m \) is given by \( m = -\frac{a}{b} \). Calculating the slopes: - For \( x + 2y + 3 = 0 \): \[ m_1 = -\frac{1}{2} \] - For \( 3x + 4y - 5 = 0 \): \[ m_2 = -\frac{3}{4} \] - For \( 2x + 4y + 5 = 0 \): \[ m_3 = -\frac{1}{2} \] - For \( 3x + 4y - 10 = 0 \): \[ m_4 = -\frac{3}{4} \] ### Step 2: Identify pairs of parallel lines From the slopes calculated: - Lines 1 and 3 are parallel (both have slope \(-\frac{1}{2}\)). - Lines 2 and 4 are parallel (both have slope \(-\frac{3}{4}\)). ### Step 3: Calculate the distance between the parallel lines The distance \( d \) between two parallel lines \( Ax + By + C_1 = 0 \) and \( Ax + By + C_2 = 0 \) is given by: \[ d = \frac{|C_2 - C_1|}{\sqrt{A^2 + B^2}} \] #### Distance between lines 1 and 3: 1. \( C_1 = 3 \) (from line 1) 2. \( C_2 = 5 \) (from line 3) Using the formula: \[ d_1 = \frac{|5 - 3|}{\sqrt{1^2 + 2^2}} = \frac{2}{\sqrt{5}} = \frac{2\sqrt{5}}{5} \] #### Distance between lines 2 and 4: 1. \( C_1 = -5 \) (from line 2) 2. \( C_2 = -10 \) (from line 4) Using the formula: \[ d_2 = \frac{|-10 + 5|}{\sqrt{3^2 + 4^2}} = \frac{5}{5} = 1 \] ### Step 4: Calculate the perimeter of the parallelogram The perimeter \( P \) of a parallelogram is given by: \[ P = 2(d_1 + d_2) \] Substituting the values: \[ P = 2\left(\frac{2\sqrt{5}}{5} + 1\right) = 2\left(\frac{2\sqrt{5}}{5} + \frac{5}{5}\right) = 2\left(\frac{2\sqrt{5} + 5}{5}\right) = \frac{4\sqrt{5} + 10}{5} \] ### Final Answer The perimeter of the parallelogram is: \[ \frac{4\sqrt{5} + 10}{5} \]
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