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On heating a mixture of NaCl, K(2)Cr(2)O...

On heating a mixture of `NaCl, K_(2)Cr_(2)O_(7)` and conc. `H_(2)SO_(4)` which of the following is formed ?

A

`CrO_(2)Cl`

B

`CrO_(2)Cl_(2)`

C

`CrOCl_(2)`

D

`NaClO_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of what is formed when a mixture of NaCl, K2Cr2O7, and concentrated H2SO4 is heated, we can break down the reactions step by step. ### Step 1: Identify the Reactants The reactants in this case are: - Sodium Chloride (NaCl) - Potassium Dichromate (K2Cr2O7) - Concentrated Sulfuric Acid (H2SO4) ### Step 2: Reaction of K2Cr2O7 with H2SO4 When potassium dichromate (K2Cr2O7) reacts with concentrated sulfuric acid (H2SO4), it produces potassium hydrogen sulfate (KHSO4), chromium trioxide (CrO3), and water (H2O). The balanced equation for this reaction is: \[ K_2Cr_2O_7 + 6 H_2SO_4 \rightarrow 2 KHSO_4 + 2 CrO_3 + 3 H_2O \] ### Step 3: Reaction of NaCl with H2SO4 Sodium chloride (NaCl) reacts with concentrated sulfuric acid (H2SO4) to produce sodium hydrogen sulfate (NaHSO4) and hydrogen chloride (HCl). The balanced equation for this reaction is: \[ NaCl + H_2SO_4 \rightarrow NaHSO_4 + HCl \] ### Step 4: Reaction of CrO3 with HCl The chromium trioxide (CrO3) produced in the previous step can react with hydrogen chloride (HCl) to form dichlorochromium (CrO2Cl2) and water (H2O). The balanced equation for this reaction is: \[ CrO_3 + 2 HCl \rightarrow CrO_2Cl_2 + H_2O \] ### Step 5: Combine the Reactions Combining all the reactions, we can summarize that: 1. K2Cr2O7 reacts with H2SO4 to produce CrO3. 2. NaCl reacts with H2SO4 to produce HCl. 3. CrO3 reacts with HCl to produce CrO2Cl2. ### Final Product Thus, when a mixture of NaCl, K2Cr2O7, and concentrated H2SO4 is heated, the main product formed is **CrO2Cl2**. ### Conclusion The correct answer to the question is **CrO2Cl2**. ---
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