Home
Class 12
CHEMISTRY
Calculate the emf of the cell in which t...

Calculate the emf of the cell in which the following reaction takes place :
`Ni(s)+2Ag^(+)(0.002M) to Ni^(2+) (0.160M) +2Ag(s)`
Given that `E_("cell")^(Theta)=1.05V`

Text Solution

Verified by Experts

The correct Answer is:
0.91
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the EMF of the cell in which the following reaction takes place : Ni(s)+2Ag^(o+)(0.002M) rarr Ni^(2+)(0.160M)+2Ag(s)

Calculate the e.m.f. of the cell in which the following reaction takes place : Ni(s) +2Ag^(+)(0.002 M)to Ni^(2+)(0.160 M)+2Ag(s) Given E_(cell)^(@) =1.05 v

Calculate the e.m.f. of the cell in which the following reaction takes place: Ni(s) + 2Ag^(+)(0.004 M) → Ni^(2+)(0.1 M) + 2Ag (s) Given that E^(@) Cell =1.05V

Represent the cell in which following reaction takes place : Mg(s)+2Ag^(o+)(0.0001M)rarr Mg^(2+)(0.130M)+2Ag(s) calculate its E_(cell) if E^(c-)._(cell)=3.17V.

Calculate the e.m.f. of a cell in which the following reactions take place at different electrodes. Zn^(2+) +2e^(-) to Zn, E^(Theta)= -0.76V " "...(i) Ag^(+)+e^(-) to Ag, E^(Theta)=0.79V" "...(ii)

Calculate the emf of the following cell reaction at 298 K: Mg(s) +Cu^(2+) (0.0001 M) to Mg^(2+) (0.001M) +Cu(s) The standard potential (E^(Theta)) of the cell is 2.71 V.

The e.m.f and the standard e.m.f of a cell in the following reaction is 5 V and 5.06 V at room temperature, Ni(s) + 2Ag^+(n) → Ni^(2+)(0.02M) + 2Ag(s) . What is the concentration of Ag+ ions?

Give the representation for the cell with cell reaction as : 2Ag^(+)+Ni to Ni^(2+)+2Ag

Calculate the E.M.F of the following cell at 298 K: Mg//Mg^(2+) (0.130 M)"||" Ag^(+) (1.0 xx 10^(-4)M) "|"Ag Given that E_((Mg^(2+)"|"Mg))^(Theta)= -2.37V, E_((Ag^(+)"|"Ag))^(@)=0.80V