The EAN of Zn in `[Zn(NH_(3))_(4)]^(2+)` is

Answer

To calculate the Effective Atomic Number (EAN) of Zn in the complex \([Zn(NH_3)_4]^{2+}\), we can follow these steps:

### Step 1: Identify the Atomic Number (Z) of Zn
The atomic number (Z) of zinc (Zn) is 30.

### Step 2: Determine the Oxidation State of Zn
In the complex \([Zn(NH_3)_4]^{2+}\), we need to find the oxidation state of Zn.
- Let the oxidation state of Zn be \(X\).
- Ammonia (NH3) is a neutral ligand, contributing 0 to the charge.
- The overall charge of the complex is +2.

The equation for the oxidation state can be set up as follows:
\[ X + 0 \cdot 4 = +2 \]
Thus, we find:
\[ X = +2 \]

### Step 3: Calculate the Number of Electrons Lost (X)
From the previous step, we have determined that the oxidation state of Zn is +2. Therefore, Zn has lost 2 electrons:
\[ X = 2 \]

### Step 4: Calculate the Number of Electrons Donated by the Ligands (Y)
Each ammonia (NH3) ligand donates 2 electrons. Since there are 4 ammonia ligands in the complex:
\[ Y = 4 \times 2 = 8 \]

### Step 5: Apply the EAN Formula
The formula for EAN is given by:
\[ \text{EAN} = Z - X + Y \]
Substituting the values we have:
- \(Z = 30\)
- \(X = 2\)
- \(Y = 8\)

Now, substituting these values into the formula:
\[ \text{EAN} = 30 - 2 + 8 \]
\[ \text{EAN} = 30 - 2 + 8 = 36 \]

### Conclusion
The Effective Atomic Number (EAN) of Zn in \([Zn(NH_3)_4]^{2+}\) is **36**.

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