In the Freundich adsorption isotherm, the value of `((1)/(n))` is between 0 and ………… .

Answer

To solve the question regarding the value of \((1/n)\) in the Freundlich adsorption isotherm, we need to understand the relationship described by this isotherm and the implications of its parameters.

### Step-by-Step Solution:

1. **Understanding the Freundlich Adsorption Isotherm**:
The Freundlich adsorption isotherm is represented by the equation:
\[ \frac{x}{m} = k p^{\frac{1}{n}} \]
where:
- \(x\) is the mass of the adsorbate,
- \(m\) is the mass of the adsorbent,
- \(p\) is the pressure of the gas,
- \(k\) and \(n\) are constants that depend on the nature of the adsorbate and adsorbent.

2. **Analyzing the Parameters**:
From the equation, we can see that the extent of adsorption \((x/m)\) is proportional to the pressure raised to the power of \((1/n)\). The parameter \(n\) is a measure of the adsorption intensity.

3. **Behavior at Low and High Pressures**:
- At **low pressure**: The relationship is approximately linear, suggesting that \(x/m\) is directly proportional to \(p\). In this case, \(1/n = 1\) (thus \(n = 1\)).
- At **high pressure**: The adsorption reaches a saturation point where the extent of adsorption becomes independent of pressure. Here, \(1/n\) approaches \(0\) (thus \(n\) approaches infinity).

4. **Intermediate Values**:
Between low and high pressures, the value of \((1/n)\) can take on values that lie between \(0\) and \(1\). This indicates that \(n\) itself will vary between \(1\) and \(\infty\).

5. **Conclusion**:
Therefore, the value of \((1/n)\) in the Freundlich adsorption isotherm lies between \(0\) and \(1\).

### Final Answer:
The value of \((1/n)\) is between \(0\) and \(1\).