Name the end product in the following series of reaction.
`CH_(3)COOHoverset(NH_(3))underset(Delta)rarr Aoverset(P_(4)O_(10))underset(Delta)rarr B`

Options

A. `CH_(4)`
B. `CH_(3)OH`
C. `CH_(3)CN`
D. `CH_(3)COONH_(4)`

Answer

To determine the end product of the given reaction series, we will analyze each step carefully.

### Step-by-Step Solution:

1. **Identify the Initial Reactant:**
The initial reactant is acetic acid (CH₃COOH).

2. **Reaction with Ammonia:**
When acetic acid reacts with ammonia (NH₃) under heat (Δ), it forms an ammonium salt. The reaction can be represented as:
\[ CH₃COOH + NH₃ \rightarrow CH₃COONH₄ \]
Here, the product A is ammonium acetate (CH₃COONH₄).

3. **Dehydration of Ammonium Acetate:**
Upon further heating, ammonium acetate undergoes dehydration, which means it loses a water molecule (H₂O). The reaction can be represented as:
\[ CH₃COONH₄ \xrightarrow{Δ} CH₃C(O)NH + H₂O \]
The product formed here is an amide, specifically acetamide (CH₃C(O)NH₂).

4. **Reaction with P₄O₁₀:**
The next step involves the reaction of acetamide with phosphorus pentoxide (P₄O₁₀), which is a dehydrating agent. This reaction leads to the removal of water and the formation of a nitrile:
\[ CH₃C(O)NH₂ \xrightarrow{P₄O₁₀} CH₃CN + H₂O \]
The end product B is methyl cyanide (also known as acetonitrile, CH₃CN).

### Final Answer:
The end product of the reaction series is **methyl cyanide (CH₃CN)**.