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An ammeter has resistance R(0) and ran...

An ammeter has resistance `R_(0)` and range l what resistance should be connected in parallel with it to increase its range by nl ?

A

`R_(0)//(n-1)`

B

`R_(0)//(n+1)`

C

`R_(0)//n`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the resistance that should be connected in parallel with an ammeter to increase its range by a factor of \( n \). ### Step-by-Step Solution: 1. **Understand the Given Parameters**: - The ammeter has an internal resistance \( R_0 \). - The original range of the ammeter is \( I \). - We want to increase the range to \( nI \). 2. **Concept of Shunt Resistance**: - To increase the range of the ammeter, we need to connect a shunt resistance \( S \) in parallel with the ammeter. This allows a portion of the current to bypass the ammeter, effectively increasing its range. 3. **Current Distribution**: - Let the total current flowing through the circuit be \( nI \). - The current through the ammeter will be \( I \) (the original current it can measure). - Therefore, the current through the shunt resistance \( S \) will be \( (nI - I) = (n - 1)I \). 4. **Voltage Drop Across the Ammeter**: - The voltage drop across the ammeter can be expressed as: \[ V = I \cdot R_0 \] 5. **Voltage Drop Across the Shunt Resistance**: - The voltage drop across the shunt resistance can be expressed as: \[ V = (n - 1)I \cdot S \] 6. **Setting the Voltage Drops Equal**: - Since both components are in parallel, the voltage drops across them must be equal: \[ I \cdot R_0 = (n - 1)I \cdot S \] 7. **Cancelling \( I \) from Both Sides**: - Assuming \( I \neq 0 \), we can divide both sides by \( I \): \[ R_0 = (n - 1)S \] 8. **Solving for Shunt Resistance \( S \)**: - Rearranging the equation gives us: \[ S = \frac{R_0}{n - 1} \] 9. **Conclusion**: - The required shunt resistance \( S \) that should be connected in parallel with the ammeter to increase its range by \( nI \) is: \[ S = \frac{R_0}{n - 1} \] ### Final Answer: The resistance that should be connected in parallel with the ammeter is \( \frac{R_0}{n - 1} \).
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