2 - Methylpent -2- ene on reductive ozonlysis will give

Options

A. Propanal only
B. Proapnal and ethanal
C. Propanone & propanal
D. Propan -2- ol and ethanal

Answer

To solve the problem of what products are formed when 2-methylpent-2-ene undergoes reductive ozonolysis, we can follow these steps:

### Step 1: Draw the Structure of 2-Methylpent-2-ene
2-Methylpent-2-ene has the following structure:
- It consists of 5 carbon atoms (pent).
- The double bond is located between the second and third carbon atoms (2-ene).
- There is a methyl group attached to the second carbon.

The structure can be represented as:
```
CH3
|
CH3-CH=C-CH2-CH3
```

### Step 2: Ozonolysis Reaction
In ozonolysis, the double bond in the alkene reacts with ozone (O3) to form an ozonide. The ozonide is an intermediate compound that will be further reduced.

### Step 3: Formation of Ozonide
When 2-methylpent-2-ene reacts with ozone, it forms an ozonide. The ozonide structure can be represented as:
```
O
||
CH3-C-CH2-CH3
|
CH3
```
This ozonide will undergo hydrolysis in the presence of zinc (Zn) and water (H2O).

### Step 4: Hydrolysis of Ozonide
During the hydrolysis, the ozonide will break down into carbonyl compounds. The cleavage of the ozonide will yield:
- Propanone (acetone) from the central carbon.
- Propanal (an aldehyde) from the terminal carbon.

The reaction can be summarized as:
- The ozonide breaks down to form propanone (C3H6O) and propanal (C3H6O).

### Step 5: Identify the Products
The products formed from the ozonolysis of 2-methylpent-2-ene are:
1. Propanone (C3H6O)
2. Propanal (C3H6O)

### Conclusion
Thus, the correct answer to the question is that 2-methylpent-2-ene on reductive ozonolysis will give propanone and propanal.

### Final Answer
**Propanone and Propanal.**

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