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The work done in adiabatic compression o...

The work done in adiabatic compression of 2 mole of an ideal monoatomic gas against constant external pressure of 2 atm starting from initial pressure of 1 atm and initial temperature of 300 K (R = 2 cal/mol-degree)

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The work done in adiabatic compression of 2 mole of an ideal monoatomic gas by constant external pressure of 2 atm starting from initial pressure of 1 atm and initial temperature of 30 K(R=2 cal//"mol-degree")

One mole of an ideal monoatomic gas at 27^(@) C expands adiabatically against constant external pressure of 1 atm from volume of 10 dm^(3) to a volume of 20 dm^(3) .

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What is the work done when 1 mole of a gas expands isothermally from 25 L to 250 L at a constant pressure of 1 atm and a temperature of 300 K ?

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One mole of an ideal monoatomic gas at temperature T and volume 1L expands to 2L against a constant external pressure of one atm under adiabatic conditions, then final temperature of gas will be:

One mole of an ideal monoatomic gas at temperature T and volume 1L expands to 2L against a constant external pressure of one atm under adiabatic conditions, then final temperature of gas will be:

One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from intial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas in 300 K then total entropy change of system in the above process is: [R=0.0082L atm mol^(-1)K^(-1)=8.3J mol^(-1)K^(-1)]