Home
Class 12
PHYSICS
A rectangular frame ABCD made of a unifo...

A rectangular frame ABCD made of a uniform metal wire has a straight connection between E & F made of the same wire as shown in the figure.
AEFD is a square of side 1 m & EB = FC = 0.5 m. The entire circuit is placed in a steadily increasing uniform magnetic field directed into the plane of the paper. The rate of change of the magnetic field is `1Ts^(-1)`, the resistance per unit length of the wire is `1Omegam^(-1)`. If the currents in the segements AE and EF and `I_(AE) and E_(EF)` respectively, then what is the value of `(I_(AE))/(I_(EF))`?

Text Solution

Verified by Experts

The correct Answer is:
7
Promotional Banner

Similar Questions

Explore conceptually related problems

A rectangular frame ABCD, made of a uniform metal wire, has a straight connection between E and F made of the samae wire, as shown in fig. AEFD is a square of side 1m, and EB=FC=0.5m. The entire circuit is placed in steadily increasing, uniform magnetic field directed into the plane of the paper and normal to it. The rate of change of the magnetic field is 1T//s . The resistance per unit length of the wire is 1omega//m . Find the magnitude and directions of the currents in the segments AE, BE and EF.

The counductor AD moves to the right in a uniform magnetic field directed into the plane of the paper.

A conducting loop carrying a current I is placed in a uniform magnetic field ponting into the plane of the paper as shown. The loop will have a tendency to

A wire is bent to form the double loop shown in figure. There is a uniform magnetic field directed into the plane of the loop. If the magnitude of this field is decreasing current will flow from:

A closed loop with the geometry shown in Fig. 3.9 is placed in a uniform magnetic field direction into the plane of the paper. If the magnetic field decreases with time, determine the direction of the induced emf in this loop.

A wire frame of given shape, carrying current of 10 A is placed in uniform magnetic field 100 T directed into the plane of paper as shown in figure. The net force acting on frame is

A long conducting wire AH is moved over a conducting triangular wire CDE with a constant velocity v in a uniform magnetic field vec(B) directed into the plane of the paper. Resistance per unit length of each wire is rho . Then

A wire is placed between the poles of twofixed bar magnets as shown in the figure. A small current in the wire is into the plane of the paper. The direction of the magnetic force on the wire is

The force exerted on a current-carrying wire placed in magnetic field is zero when the angle between the wire and the direction of magnetic field is :

There is a uniform magnetic field directed perpendicular and into the plane of the paper. An irregular shaped conducting loop is slowly changing into a circular loop in the plane of the paper. Then