Salicylic acid is produced when phenol in alcoholic KOH is treated with

Options

A. `CH_(3)Cl`
B. `CHCl_(3)`
C. `CH_(2)Cl_(2)`
D. `"CCl"_(4)`

Answer

To solve the question regarding the production of salicylic acid from phenol in alcoholic KOH, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The main reactant is phenol (C6H5OH).
- The reagent used is alcoholic KOH.

2. **Understand the Reaction Mechanism**:
- In the presence of alcoholic KOH, phenol undergoes a reaction known as the Kolbe's electrolysis or a similar reaction where phenol can be converted to salicylic acid.

3. **Formation of Salicylic Acid**:
- When phenol is treated with KOH, it can undergo a nucleophilic substitution reaction where the hydroxyl group (-OH) can be replaced or modified.
- The reaction involves the introduction of a carboxyl group (-COOH) to the phenolic compound.

4. **Final Product**:
- The final product of this reaction is salicylic acid (C7H6O3), which contains both a hydroxyl group and a carboxylic acid group on the aromatic ring.

5. **Conclusion**:
- The species that phenol is treated with in alcoholic KOH to produce salicylic acid is carbon dioxide (CO2) or a similar source of carboxylation.

### Final Answer:
The species treated with phenol in alcoholic KOH to produce salicylic acid is carbon dioxide (CO2).

---