The intermediate product (X) formed in the following reaction is
`B_(2)H_(6)+6NH_(3)rarr 3K overset("heat")rarr 2B_(3)N_(3)H_(6)+12H_(2)`

Options

A. `[BH(NH_(3))_(3)]^(+)[BH_(4)]^(-)`
B. `[BH_(2)(NH_(3))_(4)]^(+)[BH_(4)]^(-)`
C. `[BH(NH_(3))_(4)]^(+)[BH_(4)]^(-)`
D. `[BH_(2)(NH_(3))_(2)]^(+)[BH_(4)]^(-)`

Answer

To solve the question regarding the intermediate product (X) formed in the reaction of \( B_2H_6 \) with \( NH_3 \), we can break down the process step by step.

### Step 1: Understand the Reaction
The reaction given is:
\[ B_2H_6 + 6NH_3 \rightarrow 3K \]
where \( K \) is the intermediate product that will further react upon heating to yield:
\[ 3K \xrightarrow{\text{heat}} 2B_3N_3H_6 + 12H_2 \]

### Step 2: Identify the Reactants
- **Boron Hydride**: \( B_2H_6 \) (Diborane)
- **Ammonia**: \( NH_3 \)

### Step 3: Analyze the Formation of the Intermediate
When \( B_2H_6 \) reacts with \( NH_3 \), the expected intermediate product \( K \) is formed. The reaction involves the coordination of ammonia with boron hydride.

### Step 4: Write the Reaction for the Intermediate Formation
The reaction can be represented as:
\[ B_2H_6 + 6NH_3 \rightarrow 2(BH_2 \cdot NH_3) + 2BH_4^- \]
This indicates that the intermediate \( K \) can be represented as a complex of boron and ammonia.

### Step 5: Identify the Structure of the Intermediate
The intermediate \( K \) can be represented as:
\[ K = (BH_2 \cdot NH_3)_2 + BH_4^- \]
This structure indicates that the intermediate consists of boron-nitrogen bonds and is a complex of boron hydride and ammonia.

### Step 6: Finalize the Intermediate Product
The final intermediate product \( K \) can be identified as:
\[ K = (BH_2 \cdot NH_3)_2 \]
This is also known as a boron-nitrogen complex.

### Conclusion
The intermediate product \( K \) formed in the reaction is:
\[ K = (BH_2 \cdot NH_3)_2 + BH_4^- \]